Out of the sampled 30 employees 22 worked for at least 10 years.
point estimate (p^) = 22/30 = 0.73
Answer:
B, it's the only plausible one. A is wrong because the value would be above 180°
(y-y0)/(x-x0)=slope
so (85-76)/(2-(-11))=9/13
Complete Question:
The complete question is shown on the first uploaded image
Answer:
The probability that the random you randomly select species that are greater than 200 kg is = 7/62
Step-by-step explanation:
Step One: Load the data set in to the R work space
data(mammals,package="MASS")
attach(mammals)
Step 2 : Obtain the list of the species that are greater than 200 and store it on y variable.
y <- subset(mammals,body>200)
Step Three : Obtain the total size
nrow(mammals)
Step Four : Obtain the sum of species greater than 200
sum(body > 200)
total size = 62
size with body > 200 = 7
hence
required probability = 7/62
Your table of values is so difficult to read that many of us helpers would just skip your post.
<span>x f(x) -6 2.5 -2 2.5 0 2 2 0 3 5 5 2.5 1 0.5</span> could be put into far clearer format as follows:
x f(x)
-- -----
-6 2.5
-2 2.5
and so on. Please fix it.
The "average rate of change" formula is
f(x2) - f(x1)
av r of c = ---------------
x2-x1
so if you go from (-6, 2.5) to (2.5, 10.5), the av r of c would be
10.5 - 2.5 9 18
------------------ = -------- = -----
2.5-(-6) 8.5 17
This may or may not be your final answer. Again, please put your data table into readable form and then find the av r of c over the interval [-2,3].
