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2 years ago

What would be your first step in solving for x in this problem. Please EXPLAIN in words?

Mathematics

2 answers:

MrRissso [65]2 years ago

8 0

Answer:

Step-by-step explanation: distribute the 1.5 and the 2

PtichkaEL [24]2 years ago

8 0

Answer:

hey you need to multiple the number behind the parentheses by the number into the parentheses, like 1.5×2x

the you put Xs on the left side of the = and the numbers on the right side

then you do the sentence and at the end you got the amount for x :)

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Simplify rational equations y=x^2+3x/x Show work, please

lora16 [44]

Answer:

Step-by-step explanation:

2y x 3x

7 0

3 years ago

Plz help ASAP number 4 I️ have B and 7 I️ have c plz help with the rest

Veronika [31]

Answer:

5 is interpolation

hope this helps!

4 0

3 years ago

. An elevator starts at the 6th floor. It goes up 7 floors twice, and then it goes

Anettt [7]

Well let's see what floor each one lands on and figure out which one is higher.

Something to note:

down = subtracting

up = adding

if something says it's doing something more than once, add it the number of times it's doing that thing. (You can also multiply it by that number but the adding way is a bit easier to understand and explain)

Elevator 1:

6 + 7 + 7 - 10 = 10

Elevator 2:

20 - 5 - 5 - 5 + 12 = 17

Elevator 2 ends on a higher floor (reasoning above)

4 0

2 years ago

How do you find the derivative of 1/logx?

valentina_108 [34]

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

$With the chain rule. \\ 1log(x)=log(x)−1 \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\ \\−2⋅ddxlog(x) \\ =−1log(x)21x \\ =−1xlog(x)2 .$