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Arte-miy333 [17]
3 years ago
10

PLEASE HELP!!! I really need help on this, and this is one of my missing assignments that I HAVE to turn in. SO PLEASE HELP ME

Mathematics
1 answer:
Mumz [18]3 years ago
3 0

Answer:

19.99

Step-by-step explanation:

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2 women and 7 girls can do a peice of work in 4 days.4 women and 4 girls can do the same work in 3 days. How long would it take
svetlana [45]

Answer:

x: work a woman can do in 1 day

y: work a girl can do in 1  day

Then

2x + 7y =1/4

4x + 4y =1/3

4x + 14y =2/4 (1)

4x + 4y  =1/3 (2)

=> Let (1) - (2), 10y =2/4-1/3 <=>10y = 1/6 <=> y = 1/(6x10) = 1/60 (work)

=> From (2),4x = 1/3 - 4x1/60 => 4x = 16/60 => x = 4/60 (work)

=> 1 day, a woman and a girl can do: 1/60+4/60 = 5/60 =1/12 (work)

Then, the day required for a woman and a girl to complete work: 12 days

3 0
3 years ago
What is the simplified value of the exponential expression 161/4
just olya [345]

Answer:

40 1/4

Step-by-step explanation:

160 is a multiple of 4

160 / 4 = 40

40 1/4

3 0
2 years ago
Read 2 more answers
-2 • (-3)3 = ?<br><br> i really need help, I’m struggling so much in math.
Ronch [10]

Answer:

The answer would be 54

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
HELP ME PLEASE PLEASE
Ymorist [56]

Answer:

The value of x is 7 and y is 14.

Step-by-step explanation:

The steps are :

- 3x + y =  - 7 -  -  - (1)

y = x + 7 -  -  - (2)

(2)→(1)

- 3x + (x + 7) =  - 7 \\  - 3x + x + 7 =  - 7 \\  - 2x =  - 14 \\ x = 7

substitute \: x = 7 \:  \: into \:  \: (2)

y = 7 + 7 \\ y = 14

6 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
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