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Travka [436]
2 years ago
15

Which function is equivalent to g ( x ) = x 2 + 15 x - 54?

Mathematics
2 answers:
svetoff [14.1K]2 years ago
6 0

Answer:

I have solved on my own.

contains the answer to your question.

MrRa [10]2 years ago
5 0

Answer:

g(x) = (x+18)(x-3)

Step-by-step explanation:

  • g(x) = x²+15x-54
  • = x²+18x-3x+54
  • = x(x+18) -3(x+18)
  • g(x) = (x+18)(x-3)
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Calculus question?
Ann [662]
Remark
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)

Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2   Now differentiate that. It should be much easier.

Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x  I wonder if there's anything else you can do to this. If there is, I don't see it.

I suppose this is possible.
y' = 3/x^(1/2) + 6x

y' = \frac{3 + 6x^{3/2}}{x^{1/2}}

Frankly I like the first answer better, but you have a choice of both.
5 0
2 years ago
Hey I am super confused about the equation below. plzz help!!!
marshall27 [118]

Answer:

50.

Step-by-step explanation:

12 x 45 = 540. 45 + 5 = 50.

5 0
2 years ago
What's the area of the composite figure below ?
JulsSmile [24]

Answer:

31.13

Step-by-step explanation:

If you look carefully, you will find a semicircle and a triangle.

The total area is =

\frac{\pi r^{2}}{2} + \frac{1}{2} \times base \times height\\

  • r = 4 - 0 = 4
  • base = |-4-0 | = 4
  • height = 14 - 9 = 5

So if we put the values:

\frac{\pi \times 4^{2}}{2} + \frac{1}{2} \times 4 \times 3\\= 31.13

3 0
3 years ago
The equation ( ) has no solution.
trasher [3.6K]

Answer:

i dont see the equation

Step-by-step explanation:

sorry

6 0
3 years ago
Read 2 more answers
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
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