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olasank [31]
3 years ago
13

4x + 33 = 10x + 3 show your work

Mathematics
2 answers:
asambeis [7]3 years ago
7 0

Answer:

on 4x + 33 = 10x + 3, we could use inverse operation and move 10x to left side, which will create -6x+33=3. we could also use the same thing to 33 and get -6x=-30. if we divide -30 by -6, we would get 5

Step-by-step explanation:

Masteriza [31]3 years ago
6 0

4+33=10+3

4+33−33=10+3−33

4=10−3

=5

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egoroff_w [7]
-3*-5 = 15 

<span>When the signs are the same the answer is positive.</span>
5 0
4 years ago
Answer the following true or false. Justify your answer.
Anna007 [38]

Answer:

a) False b) False c) True d) True e) True

Step-by-step explanation:

a) If A is a subset of B, and x∈B, then x∈A. False

Suppose A is Z (Set of Integers), and B is R (Set of Real Numbers). Then A is a subset of B. x ∈ B, let's say x equals π. If x ∈ B (B = Real Numbers) and x=π then x ∉ A (Z).

We could call A, any other subset of Real numbers (Q, I,..) and we both would come up to the same conclusion when it comes to Real numbers the Set.

So this conclusion is False. Not always an element of a subset is an element of a set.

b) False

For this one, I've drawn some lines, and it is useful to work with them.

Given the set {(x,y) ∈ R²| 0<x<0} then all negative and positive numbers but zero belong to this set.

c) If A and B are square matrices, then AB is also square. True

Taking into account the rules for multiplying matrices. The number of columns of A must be the same number of lines of B to there can be a matrix product.

Whenever we multiply square matrices, we'll always get square matrices. Then this conclusion is true.

d) A and B are subsets of a set S, then A∩B and A∪B are also subsets of S. True

Suppose A= Z (Integer Numbers) and B=Q (Rational Numbers) and S= R (Real Numbers)

A∩B = Z∩Q=∅ and A∪B =Z∪Q = subset

Since the ∅ empty set ⊂ in every set and ZUQ is another Subset of R this is a True conclusion.

e) True. For a matrix A, we define A²= AA

For any Power of Matrices, all we have to do is multiply any given matrix by itself for a given number of times.

M²=M*M

M³=M*M*M

7 0
3 years ago
Solve x2 – 3x - 108 = 0.
rewona [7]
X=12, -9 I hope this somewhat helps you :)
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3 years ago
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mel-nik [20]
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7 0
2 years ago
Is floor(x) periodic?
diamong [38]

If you look at the graph of y = floor(x), you'll see a stairstep pattern that climbs up as you read from left to right. There are no vertical components to the graph. There are only horizontal components.

The graph is not periodic because the y values do not repeat themselves after a certain x value is passed. For instance, start at x = 0 and go to x = 3. You'll see the y values dont repeat themselves as if a sine function would. If you wanted the function to be periodic, the steps would have to go downhill at some point; however, this does not happen.

Conclusion: The function floor(x) is <u>not</u> periodic.

4 0
3 years ago
Read 2 more answers
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