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bixtya [17]
2 years ago
12

65÷5=____ with ____ left over​

Mathematics
1 answer:
Molodets [167]2 years ago
7 0

65 ÷ 5 = 11 with 0 left over​

Hope this helps! ;)

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How do you simply -12x=12x into an x='s answer?
dedylja [7]

-12x = 12x

Start by moving all the terms with the variable you want to solve for on one side of the equation and the rest on the other side of the equation.

We will move 12x to the left side of the equation by subtracting 12x from both sides. Now your equation should look like:

-24x = 0

Isolate the variable x by dividing both sides by -24. Everything divided by 0 is equal to 0, so that means x will be equal to 0.

x = 0

Your answer is x = 0.

3 0
3 years ago
Solve the equation: Sin2x - Sinx = 0
Viktor [21]
We know that sin2x=2sinxcosx 
(search the net for proof if you wish) 

So the original equation becomes

2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get: 

sinx(2cosx-1)=0 
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sinx=0 than x=2kπ
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5 0
3 years ago
Please I neeed help
Novosadov [1.4K]
The answer is 59049 hope this helps
8 0
2 years ago
Read 2 more answers
Plssss helpppp me on this last answererrr
Oksanka [162]
The answer is y= -3x-3
Please mark as BRAINLIEST!
4 0
2 years ago
Tesla Battery Recharge Time.The electric­ vehicle manufacturing company Tesla esti­mates that a driver who commutes 50 miles per
madam [21]

Answer:

a.) f(x) = \frac{1}{30} where 90 < x < 120

b.) \frac{2}{3}

c.)  \frac{2}{3}

d.)  \frac{1}{2}

Step-by-step explanation:

Let

X be a uniform random variable that denotes the actual charging time of battery.

Given that, the actual recharging time required is uniformly distributed between 90 and 120 minutes.

⇒X ≈ ∪ ( 90, 120 )

a.)

Probability density function , f (x) = \frac{1}{120 - 90} = \frac{1}{30} where 90 < x < 120

b.)

P(x < 110) = \int\limits^{110}_{90} {\frac{1}{30} } \, dx

               = \frac{1}{30}[x]\limits^{110}_{90}  = \frac{1}{30} [ 110 - 90 ] = \frac{1}{30} [ 20] = \frac{2}{3}

c.)

P(x > 100 ) = \int\limits^{120}_{100} {\frac{1}{30} } \, dx

                 = \frac{1}{30}[x]\limits^{120}_{100}  = \frac{1}{30} [ 120 - 100 ] = \frac{1}{30} [ 20] = \frac{2}{3}

d.)

P(95 < x< 110)  = \int\limits^{110}_{95} {\frac{1}{30} } \, dx

                       = \frac{1}{30}[x]\limits^{110}_{95}  = \frac{1}{30} [ 110 - 95 ] = \frac{1}{30} [ 15] = \frac{1}{2}

7 0
3 years ago
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