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bixtya [17]
3 years ago
12

65÷5=____ with ____ left over​

Mathematics
1 answer:
Molodets [167]3 years ago
7 0

65 ÷ 5 = 11 with 0 left over​

Hope this helps! ;)

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-9u^7v - 6u^5v - 21u^2v

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  1. CONSTRUCT FROM A TO B AND ALSO A TO C AND B TO C
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Liza went out for pizza with her mom. Their meal cost $32. Sales tax is 5% and they decide to leave 15%
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3 years ago
If the probability that your DVD player breaks down before the extended warranty expires is 0.034, what is the probability that
schepotkina [342]

Answer:

0.966

Step-by-step explanation:

Given that:

Probability of DVD player breaking down before the warranty expires = 0.034

To find:

The probability that the player will not break down before the warranty expires = ?

Solution:

Here, The two events are:

1. The DVD player breaks down before the warranty gets expired.

2. The DVD player breaks down after the warranty gets expired

In other words, the 2nd event can be stated as:

The DVD does not break down before the warranty gets expired.

The two events here, have nothing in common i.e. they are mutually exclusive events.

So, Sum of their probabilities will be equal to 1.

\bold{P(E_1)+P(E_2)=1}\\\Rightarrow 0.034+P(E_2)=1\\\Rightarrow P(E_2)=1-0.034\\\Rightarrow P(E_2)=\bold{0.966}

7 0
3 years ago
In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta
Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.3246

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0
2 years ago
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