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3 years ago

A^2 + 2a^2 = b^2 solve for b

Mathematics

2 answers:

lesantik [10]3 years ago

7 0

Answer:

b=a √3

Step-by-step explanation:

Murljashka [212]3 years ago

5 0

B= root square everything —-> a^2+ 2a^2

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Somebody help please

Vesnalui [34]

Answer:

if that says plus 60 cents then she pledged 455 dollars

Step-by-step explanation:

5 0

3 years ago

Let z≥2. What is the remainder of 10^z −1 divided by 4?

DerKrebs [107]

Answer:

The remainder is 3.

Step-by-step explanation:

We have to find out,

$10^z-1(mod 4)=?\text{ where }z\geq 2$

If z = 2,

$10^{2}-1=100-1=99$

∵ 99 ( mod 4 ) = 3,

Suppose,

$(10^{k}-1)(mod 4)=3\forall \text{ k is an integer greater than 2,}$

Now,

$(10^{k+1}-1) ( mod 4)$

$= (10^k.10 - 10+9)(mod 4)$

$= 10(mod 4)\times (10^k-1)(mod 4 ) + 9 ( mod 4)$

$= (2\times 3)(mod 4) + 1$

$=2+1$

$=3$

Hence, our assumption is correct.

The remainder of $10^z -1$ divided by 4 is 3 where, z ≥ 2.

7 0

3 years ago

Bob travels from Inglewood to Anytown, a distance of 20kilometres, he walks 800 metres and bicylces the rest of the way. what pe

sukhopar [10]

For this case we have the following conversion:

$1 km = 1000m$

Therefore, for 20 kilometers we have:

$(20) (1000) = 20000 m$

Then, we have the following relationship:

$800 + x = 20000$

Where,

x: distance Bob travels by bicycle

Clearing x we have:

$x = 20000 - 800\\x = 19200$

Then, the percentage that Bob travels by bicycle is:

$(\frac{19200}{20000}) * (100) = 96$ %

Answer:

The percentage that Bob travels in bicycle is 96%.

5 0

4 years ago

3 cards are drawn from a standard deck of 52 cards. Find the probability of drawing either 3 red cards or 3 face cards.

Mamont248 [21]

Answer:

The probability of drawing either 3 red cards or 3 face cards is 0.1276.

Step-by-step explanation:

Total number of card in standard deck is 52.

Number of red cards is 26.

Face card are king, queen and jack. Total number of face cards are $3\times 4=12$ .

Formula of probability is

$P=\frac{\text{Number of possible outcomes}}{\text{Total outcomes}}$

$^nC_r=\frac{n!}{r!(n-r)!}$

Total outcomes is

$^{52}C_3=\frac{52!}{3!(52-3)!}=22100$

Total possible outcomes of getting 3 red is

$^{26}C_3=\frac{26!}{3!(26-3)!}=2600$

Total possible outcomes of getting 3 face is

$^{12}C_3=\frac{12!}{3!(12-3)!}=220$

Total possible outcomes of getting either 3 black or 3 face cards is

$2600+220=2820$

probability of drawing either 3 red cards or 3 face cards is

$\frac{2820}{22100}=0.12760181\approx 0.1276$

probability of drawing either 3 red cards or 3 face cards is 0.1276.

6 0

4 years ago

Read 2 more answers

140 is what percent of 500?

MAXImum [283]

Answer:

28%

Step-by-step explanation:

5 0

3 years ago