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Anton [14]
3 years ago
11

Tanya and three friends have saved $75 to help protect the pandas. If they each gave the same amount, how much did each person c

ontribute?
Mathematics
1 answer:
Ber [7]3 years ago
8 0

Answer:

Step-by-step explanation:

If it is Tanya and 3 friends, there are 4 people in total. If they all contributed the saem amount, you would do 75/4= 18.75 dollars each

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Is 1:4 equivalent to 8:64
RUDIKE [14]
The answer is no

Simplify 8/64= 1/8= 0.125

1/4= 0.25
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3 years ago
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51. q(x) = 2 * (x - 1) ^ 2 + 5 , what is the value of q(- 3) ?
Sloan [31]

Answer:

26.69

Step-by-step explanation:

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3 years ago
Find the area of the figure​
statuscvo [17]
I just looked it up and it said it is 180
3 0
3 years ago
I don't know how to solve it.
Nataly [62]

Step-by-step explanation:

Take the first derivative

\frac{d}{dx} ( {x}^{3}  - 3x)

3 {x}^{2}  - 3

Set the derivative equal to 0.

3 {x}^{2}  - 3 = 0

3 {x}^{2}  = 3

{x}^{2}  = 1

x = 1

or

x =  - 1

For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).

For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.

Since we are going to Positve to negative slope, we have a local max at x=-1

Plug in -1 for x into the original function

( - 1) {}^{3}  - 3(  - 1) = 2

So the local max is 2 and occurs at x=-1,

For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.

Since we are going to decreasing to increasing, we have minimum at x=1,

Plug in 1 for x into original function

{1}^{3}   - 3(1)

1 - 3 =  - 2

So the local min occurs at -2, at x=1

8 0
2 years ago
Find the upper limit for the zeros of the function P(x)=4x^4+8x^3-7x^2-21x-9
pishuonlain [190]

Answer:

OPTION B - 2

Step-by-step explanation:

What is the upper limit for the zeros of the function P(x) = 4x^4 + 8x^3 - 7x^2 - 21x - 9. Ans: 2 is an upper limit. Use synthetic division. and the remainder are all positive, 2 is an upper limit.

3 0
3 years ago
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