Solve the equation.round to the nearest thousandths -5+2in(3x)=5

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Soloha48 [4]

Answer: 26 Fn²

Step-by-step explanation:

simple

5 0

2 years ago

Read 2 more answers

Please Help Me Out Show You Work :) I will appreciate much

liberstina [14]

Step-by-step explanation:

6)

$k = \frac{6}{4} \\ k = \frac{3}{2}$

7)

$\frac{ab}{mn} = \frac{bc}{no} = \frac{cd}{op} = \frac{da}{pm}$

8)

$y = 8 ( \frac{3}{2} ) \\ y = 12$

$z = 6 ( \frac{3}{2} ) \\ z = 9$

9)

$5k = 8 \\ k = \frac{8}{5} \\ x( \frac{8}{5}) = 32 \\ x = 20ft$

5 0

2 years ago

Addison budgets $120 for circus training. She buys a book about the art of juggling for $12 and pays $25 per circus class. Write

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

6 0

2 years ago

The word geometry comes from the greek words geo, which means "earth," and metron, which means "a measuring of." given this info

Leokris [45]

The geometry was developed by a Greek mathematician called Euclid and developed to meet some practical need in surveying, construction, astronomy, and various crafts.

In this question,

Early geometry was a collection of empirically discovered principles concerning lengths, angles, areas, and volumes, which were developed to meet some practical need in surveying, construction, astronomy, and various crafts.

It was developed by a Greek mathematician called Euclid. This branch of geometry deals with terms like points, lines, surfaces, dimensions of the solids, etc.,

In several ancient cultures there developed a form of geometry suited to the relationships between lengths, areas, and volumes of physical objects. This geometry was codified in Euclid's Elements about 300 bce on the basis of 10 axioms, or postulates, from which several hundred theorems were proved by deductive logic.

Hence we can conclude that the geometry was developed by a Greek mathematician called Euclid and developed to meet some practical need in surveying, construction, astronomy, and various crafts.

Learn more about geometry here

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6 0

1 year ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

7 0

3 years ago