Answer: 272
Step-by-step explanation:
Let a1=11
a2=20
a3=29
Formula for sequence=
an=a1+(n-1)d
an = nth term
a1= first term
n= nth position
d= common difference
We are looking for the 30th term,so our n=30
d= a2-a1
d= 20-11
d= 9
Using the formula
an= a1+(n-1)d
a30= 11+(30-1)9
a30= 11+(29)9
a30= 11+(29×9)
a30= 11+261
a30= 272
Therefore, the 30th term is 272
Answer:
186 and 187
Step-by-step explanation:
Let n be the first integer.
Then n+1 is the next integer.
We are given their sum is 373.
n+(n+1)=373
Combine like terms:
2n+1=373
Subtract 1 on both sides:
2n=372
Divide both sides by 2:
n=186
So n+1=187.
187
+186
--------
373
3 3/4
= 3+ 3/4
= 3+ 0.75
= 3.75
The length as a decimal is 3.75 m~
Step-by-step explanation:
The solution is in the attached file
