3 years ago

Need help on this please

Mathematics

1 answer:

Alex17521 [72]3 years ago

6 0

Answer:

(x+8) ² + $y^{2}$ = 64

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Solve 5.4p+13.1=−2.6p+3.5 . Check your solution. p= __

maxonik [38]

5.4p +13.1 = −2.6p+3.5 .

5.4p + 2.6p = 3.5 -13.1

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Solve: x + y = 7 3x - 2y = 11 By using Substituting method.

Salsk061 [2.6K]

$\large\underline{\sf{Solution-}}$

$\sf \longmapsto x + y = 7 \: \: - - - (i)$

$\sf \longmapsto 3x - 2y = 11 \: \: - - - (ii)$

By first equation,

$\sf \longmapsto x + y = 7$

$\sf \longmapsto x = 7 - y$

Now, we can find the original value of y.

$\sf \longmapsto 3x - 2y = 11$

$\sf \longmapsto 3(7 - y) - 2y = 11$

$\sf \longmapsto 21 - 3y - 2y = 11$

$\sf \longmapsto 21 - 5y = 11$

$\sf \longmapsto - 5y = 11 - 21$

$\sf \longmapsto - 5y = - 10$

$\sf \longmapsto y = \dfrac{ - 10}{ - 5}$

$\sf \longmapsto y = 2$

Now, we can find the original value of x.

$\sf \longmapsto x + y = 7$

$\sf \longmapsto x + 2 = 7$

$\sf \longmapsto x = 7 - 2$

$\sf \longmapsto x = 5$

Therefore, the values of x and y are 5 and 2 respectively.

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