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BaLLatris [955]
4 years ago
13

How to find function value?

Mathematics
1 answer:
raketka [301]4 years ago
7 0

Answer:Google it

Step-by-step explanation:EASY

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Orlov [11]
4a-87=a

3a=87

a=87/3=29
5 0
3 years ago
the population of a town is increasing at a rate of 3.4% every year. is this and example of a linear function, an exponential fu
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It would be linear because it’s moving constantly at the same rate and not changing
6 0
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Three sides of a quadrilateral are the same length, g, The length of the fourth side is 7 inches,
Ulleksa [173]

Answer:

Step-by-step explanation:

Let s represent the length of each of the three sides mentioned.  The length of the fourth side is 7 inches.  Adding the lengths of the four sides together yields 10 inches:  g + g + g + 7 = 10 (inches)

Then 3g + 7 = 10, or 3g = 3, or g = 1.  

This equation is OK, but there's no solution, since 3g or just 3 is less than 7.  With side lengths 1, 1, 1, 7, we cannot draw a quadrilateral.

8 0
3 years ago
Find the zeros of the following polynomial functions, with their multiplicities. (a) f(x)= (x +1)(x − 1)(x² +1) (b) g(x) = (x −
larisa [96]

Answer:

a) zeros of the function are x = 1 and, x = -1

b) zeros of the function are x = 2 and, x = 4

c) zeros of the function are x = \frac{3}{2}

d) zeros of the function are x = \frac{-4}{3}  and, x = 17

Step-by-step explanation:

Zeros of the function are the values of the variable that will lead to the result of the equation being zero.

Thus,

a) f(x)= (x +1)(x − 1)(x² +1)

now,

for the (x +1)(x − 1)(x² +1) = 0

the condition that must be followed is

(x +1) = 0 ..........(1)

or

(x − 1) = 0 ..........(2)

or

(x² +1) = 0 ...........(3)

considering the equation 1, we have

(x +1) = 0

or

x = -1

for

(x − 1) = 0

x = 1

and,

for (x² +1) = 0

or

x² = -1

or

x = √(-1)         (neglected as it is a imaginary root)

Thus,

zeros of the function are x = 1 and, x = -1

b) g(x) = (x − 4)³(x − 2)⁸

now,

for the (x − 4)³(x − 2)⁸ = 0

the condition that must be followed is

(x − 4)³ = 0 ..........(1)

or

(x − 2)⁸ = 0 ..........(2)

considering the equation 1, we have

(x − 4)³ = 0

or

x -4 = 0

or

x = 4

and,

for (x − 2)⁸ = 0

or

x - 2 = 0

or

x = 2        

Thus,

zeros of the function are x = 2 and, x = 4

c) h(x) = (2x − 3)⁵

now,

for the (2x − 3)⁵ = 0

the condition that must be followed is

(2x − 3)⁵ = 0

or

2x - 3 = 0

or

2x = 3

or

x = \frac{3}{2}

Thus,

zeros of the function are x = \frac{3}{2}

d)   k(x) =(3x +4)¹⁰⁰(x − 17)⁴

now,

for the (3x +4)¹⁰⁰(x − 17)⁴ = 0

the condition that must be followed is

(3x +4)¹⁰⁰ = 0 ..........(1)

or

(x − 17)⁴ = 0 ..........(2)

considering the equation 1, we have

(3x +4)¹⁰⁰ = 0

or

(3x +4) = 0

or

3x = -4

or

x = \frac{-4}{3}

and,

for (x − 17)⁴ = 0

or

x - 17 = 0

or

x = 17        

Thus,

zeros of the function are x = \frac{-4}{3}  and, x = 17

7 0
3 years ago
Is the function increasing or decreasing over the interval [-3, -1)? Explain.
olga nikolaevna [1]

Answer:I actually don’t know

Step-by-step explanation:

4 0
3 years ago
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