Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer:
The answer to your question is 600 cups
Step-by-step explanation:
Data
Cylinder Cup
diameter = 30 in diameter = 3 in
height = 24 in height = 4 in
Process
1.- Calculate the volume of the cylinder
Volume = πr²h
-Substitution
Volume = (3.14)(30/2)²(24)
-Simplification
Volume = (3.14)(15)²(24)
Volume = (3.14)(225)(24)
-Result
Volume = 16959 in³
2.- Calculate the volume of the cup
Volume = (3.14)(3/2)²(4)
-Simplification
Volume = (3.14)(1.5)²(4)
Volume = (3.14)(2.25)(4)
-Result
Volume = 28.26 in³
3.- Divide the volume of the cylinder by the volume of the cup
Number of full cups = 16959 in³ / 28.26 in³
Number of full cups = 600
Answer: 48,60
Step-by-step explanation:
4x+5x=108
9x=108
x=108/9=12
12•4=48
12•5=60
0.25 is rational because it is a terminating (means 'its stops') fraction.
X in this equation equals 140°