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kompoz [17]
3 years ago
11

a = cost of one adult’s ticket to the zoo, a-4= cost of one childrens ticket to zoo, 2a + 4(a - 4)=38. write a word problem.

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0
A group of 2 adult and 4 kids went to the zoo and paid $38 for their tickets. The kids ticket cost $4 less than adults ticket.
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Emery Mining Inc. recently reported $147,500 of sales, $75,500 of operating costs other than depreciation, and $10,200 of deprec
Molodets [167]

Answer:

net income is $48452.81

Step-by-step explanation:

Sales =$147500

subtract operating expenses

-$75500 =$72000

subtract non- operating costs

depreciation -$10200 =$61800

-interest expense payable (16500*7,23%)$1196.25=63603.75

from profit before tax deduct income taxes =63603.75*25%=15150.9375

Net Income is therefore $63603.75-$15150.9375 = $48452.81

6 0
4 years ago
A) In a group of 60 students, 15 liked maths only, 20 liked science only and 5 did not like
Paladinen [302]

Part (i)

We have 60 students total, and 5 didn't like any of the two subjects, so that must mean 60-5 = 55 students liked at least one subject.

<h3>Answer: 55</h3>

=========================================================

Part (ii)

We have 15 who like math only, 20 who like science only, and 55 who like either (or both). Let x be the number of people who like both classes.

We can then say

15+20+x = 55

x+35 = 55

x = 55-35

x = 20

This means 20 people liked both subjects

<h3>Answer: 20</h3>

=========================================================

Part (iii)

There are 15 people who like math only, and 20 who like both. Therefore, there are 15+20 = 35 people who like math (and some of these people also like science)

<h3>Answer: 35</h3>

=========================================================

Part (iv)

We'll follow the same idea as the previous part. There are 20 people who like science only and 20 who like both subjects. That yields 40 people total who like science (and some of these people also like math).

<h3>Answer: 40</h3>

=========================================================

Part (v)

We'll draw a rectangle to represent the entire group of 60 students. This is considered the universal set. Inside the rectangle will be two overlapping circles to represent math (M) and science (S).

We'll have 15 go in circle M, but outside circle S to represent the 15 people who like math only. Then we have 20 go in circle S but outside circle M to show the 20 people who like science only. We have another copy of 20 go in the overlapped region between the circles. This is the 20 people who like both classes. And finally, we have 5 go outside both circles, but inside the rectangle. These are the 5 people who don't like either subject.

Note how all of the values in the diagram add up to 60

15+20+20+5 = 60

This helps confirm we have the correct values.

<h3>Answer: See the venn diagram below</h3>

3 0
3 years ago
Aubrey ran 13 1/6 miles and walked 9 5/6 miles. How much farther did Aubrey run than walk?
leonid [27]

Answer:

Aubrey ran 3 1/3 miles further than what she walked.

Step-by-step explanation:

This would be your basic subtraction problem. So, 13 1/6 - 9 5/6.

Since you can't subtract 5/6 from 1/6, let's borrow from 13. Now, instead of 13, it would be 12. Adding the whole (1) or 6/6 to the 1/6, you'll get 7/6. Now you can subtract. 7/6 - 5/6 = 2/6. Moving on, 12 - 9 = 3.

Therefore, your answer is 3 2/6. In simplified terms, it would be 3 1/3.

3 0
2 years ago
Given that
VLD [36.1K]

-17/2

Step-by-step explanation:

30-8(8)+4y

30=64+4y

30-64=4y

-34=4y

y= -34/4

y= -17/2

hope it helps!

6 0
3 years ago
What is the distance between p(-300, 200) and Q(500, 400)?
alina1380 [7]

Answer:

200 √17

Step-by-step explanation:

distance between two points (x,y) and (x',y')

D² = (x' - x)² + (y' - y)²

D² = (500 - (-300))² + (400 - 200)² = 640000 + 40000 = 680000

D = √680000 = √4 x 17 x 10000 = 200 √17

7 0
4 years ago
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