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3 years ago

5

Giselle is building a small baseball infield for her brother. The infield should be in the shape of a square. Each side of the i

nfield, between bases, measures 30 feet. The distance between home plate and second base, as shown in the picture, is 45 feet. A square has points home plate, first base, second base, third base. The distance between home plate and second base is 45 feet. The distance between home plate and first base is 30 feet. Which best describes the shape of the baseball field? Square: 30 squared + 30 squared = 45 squared Not square: (30 + 30) squared not-equals 45 squared Not square: 2 (30) squared not-equals 45 squared Not square: (2 times 30) squared not-equals 45 squared

2 answers:

matrenka [14]3 years ago

7 0

Answer:

c

Step-by-step explanation:

right on edge2020

kotykmax [81]3 years ago

3 0

Answer:

The Awnser is C

Step-by-step explanation:

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Kedar eaens a monthly salary of $2,200 plus a 3.75% commission on the amount of his sales at a men's clothing store . What would

NemiM [27]

Okay. So, Kedar earns a monthly salary of $2,200 per month. That stays the same. He earns a 3.75% monthly commission on how much he sells. To find out how much his commission would be if he sold $4,500 in clothing, we would have to multiply 4,500 by 3.75% (0.0375). When you multiply both numbers, you get $168.75 in commission sales. Now, you must add that plus 2,200. When you add both of those numbers, you get 2,368.75. Kedar would earn $2,368.75 this month if he sold $4,500 worth of clothes.

5 0

4 years ago

the mendez family just bought a home for 180,000 if the value of the home increases at a rate of 3% per year, use an exponential

just olya [345]

Answer:

241904.9483

≈ 241905

Step-by-step explanation:

Given that,

current amount of house = 180,000

value of the home increases at a rate of 3% per year

To find,

approximate value of the home after 10 years using exponential function

<h2>Equation</h2><h2>a(1 + r)^t</h2>

where a is the amount of house = 180,000

r is the interest rate per annum = 3% = 3/100 = 0.03

t is the number of years = 10

180,000 (1+0.03)^10

180,000 (1.03)^10

241904.9483

≈ 241905

<h2 />

8 0

3 years ago

A number is first increased by 20 and then doubled. The result is 2 less than 5 times the number.

torisob [31]

Answer:

The number is 14

Step-by-step explanation:

Let n be the number. We can set up an equation:

2(n+20)=5n-2

Distribute the left side

2n+40=5n-2

Move like terms to one side. Note that the sign flips when we move a term from one side to the other.

40+2=5n-2n

42=3n

Divide both sides by 3

n=14

5 0

3 years ago

The sum of two integers is -1. The first number plus 3 times the second is 67. What are the two numbers?

Alexandra [31]

Answer:

x=35

y=34

Step-by-step explanation:

x+y=-1

x+3y=67

x=-3y+67

-3y+67+y=-1

-2y+67=-1

-2y=-68

y=34

x=-35

3 0

3 years ago

Rothamsted Experimental Station (England) has studied wheat production since 1852. Each year many small plots of equal size but

podryga [215]

Answer:

(a) 0.653

(b) 0.0198

(c) Yes, after testing we conclude that the population variance of annual wheat production for the first plot is larger than that for the second plot.

Step-by-step explanation:

(a) We are give the sample of one year annual production of wheat (in pounds) ;

4.46, 4.21, 4.40, 4.81, 2.81, 2.90, 4.93, 3.54, 4.16, 4.48, 3.26, 4.74, 4.97, 4.02, 4.91, 2.59

For calculating sample variance, firstly we will calculate mean of the above data;

Mean of above data, $X_1bar$ = Sum of all values ÷ n (no. of values)

= $\frac{4.46 + 4.21+4.40+.......+4.91+2.59}{16}$ = 4.074

Sample Variance, $s_1^{2}$ = $\frac{\sum (X-X_1bar)^{2} }{n-1}$ = $\frac{(4.46-4.074)^{2}+(4.21-4.074)^{2}+.........+(4.91-4.074)^{2}+(2.59-4.074)^{2} }{16-1}$ = 0.653

(b) Another sample for annual wheat production (in pounds);

3.89, 3.81, 3.95, 4.07, 4.01, 3.73, 4.02, 3.78, 3.72, 3.96, 3.62, 3.76, 4.02, 3.73, 3.94, 4.03

Mean of above data, $X_2bar$ = Sum of all values ÷ n (no. of values)

= $\frac{3.89+3.81+3.95.......+3.94+4.03}{16}$ = 3.88

Sample Variance, $s_2^{2}$ = $\frac{\sum (X-X_2bar)^{2} }{n-1}$ = $\frac{(3.89-3.88)^{2}+(3.81-3.88)^{2}+.........+(3.94-3.88)^{2}+(4.03-3.88)^{2} }{16-1}$ = 0.0198

(c) Now, we have to test the claim that population variance of annual wheat production for the first plot is larger than that for the second plot i.e.;

Null Hypothesis, $H_0$ : $\sigma_1^{2} = \sigma_2^{2}$ or $H_0$ : $\frac{\sigma_1^{2} }{\sigma_2^{2} } = 1$

Alternate Hypothesis, $H_0$ : $\sigma_1^{2} > \sigma_2^{2}$ or $H_0$ : $\frac{\sigma_1^{2} }{\sigma_2^{2} } > 1$

The test statistics used here is;

$\frac{s_1^{2} }{s_2^{2} }* \frac{\sigma_1^{2} }{\sigma_2^{2}}$ ~ $F_n__1-1_,n_2-1$ where, $n_1 = 16$ and $n_2 =16$

Test Statistics = $\frac{0.653 }{ 0.0198}* 1$ ~ $F_1_5_,_1_5$

= 32.98

Since, we are not provided with any significance level so we assume it to be 5% and at this level, the F table gives critical value of 2.4282.

<em>Since our test statistics is higher than the critical value and it falls in the rejection region so we have sufficient evidence to reject null hypothesis and conclude that the population variance of annual wheat production for the first plot is larger than that for the second plot.</em>

8 0

3 years ago