Total outcome is 50 [because the number produced by the machine is from 1 to 50]
Question a:
Multiple of 10 are 10, 20, 30, 40, 50
There are five possible outcomes for multiple of 10
P(Multiple of 10) = 5/50 = 1/10
Question b:
Number 1 to 50 will be all the outcomes that are not 100
There are 50 possible outcomes
P(not 100) = 50/50 = 1
Question c:
Multiple of 4 that are less than 50 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48
There are 12 possible outcomes for multiple of 4
We want 'not multiple of 4' so we need to do 50 - 12 = 38 outcomes
P(not a multiple of 4) = 38/50 = 19/25
Question d:
One digit numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9
There are 9 possible outcomes
P(one-digit number) = 9/50
Answer:
after one day, 96.8 % are still there
and from this portion will remain 96.8% one day later
so you multiply 0.968 by itself seven times
0,968^7 = 0.7964
<h3>After one week there are 79.64 % left.</h3>
Answer:
10 prob?
Step-by-step explanation:
Answer:
Step-by-step explanation:
we know that
The measure of central angle ABC is 
radians
so
subtends the complete circle
The area of the shaded sector is the area of a quarter circle
so
The area of a quarter circle is equal to
we have
substitute
