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Liono4ka [1.6K]

3 years ago

7

which of the following expressions represents the product of 3 less than twice x and 2 more than the quantity 3 times x?

1 answer:

kicyunya [14]3 years ago

7 0

First, take a look at 3 less than twice x. Twice x would be 2x and 3 less than it would become 2x-3.

Next, 2 more than the quantity 3 times x. The quantity of 3 times x is 3x and 2 more than that would be 3x+2.

Now that we have our two equations, we need to multiply them together, which can be shown as (2x-3)(3x+2).

Then, multiply the two equations together using FOIL (multiply the first two terms, then the outside terms, then inside, and lastly, the last two terms): 2x times 3x, 2x times 2, -3x times 3x, and 2 times -3, which equates to 6x^2+4x-9x-6.

Your final answer is 6x^2-5x-6.

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Step-by-step explanation:

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3 years ago

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zubka84 [21]

Answer:

$z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028$

$z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441$

An we can use the normal standard table and the following difference and we got this result:

$P(-1.028$

Step-by-step explanation:

Assuming this statement to complete the problem "with a standard deviation 5 mpg"

We have the following info given:

$\mu = 34$ represent the mean

$\sigma= 5$ represent the deviation

We have a sample size of n = 54 and we want to find this probability:

$P(33.3 < \bar X< 34.3)$

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And we can use the z score formula given by:

$z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028$

$z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441$

An we can use the normal standard table and the following difference and we got this result:

$P(-1.028$

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