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3 years ago

The measures of the angles of a triangle are shown in the figure below. Find the measure of the smallest angle.

Mathematics

2 answers:

Aliun [14]3 years ago

7 0

^^ that’s correct btw

nataly862011 [7]3 years ago

4 0

Answer:

(2x+18) degrees

Step-by-step explanation:

A triangle is a total of 180 degrees, so you would do:

(2x+18)+55+(4x+11)=180

(2x+4x)+(18+55+11)=180 <- take out parentheses and add like terms

6x+84=180 <- subtract 84 from both sides of the equation

6x=96 <- divide 6 from each side

x=16

Now that you know what x is you would plug it into each of the angles

Angle 1: 2x+18 --> 2(16)+18= 32+18= 50

Angle 2: 55

Angle 3: 4x+11 --> 4(16)+18= 64+18= 82

Then out of these three angles of the triangle, angle 1 (2x+18) would be the smallest.

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What’s the area of a rectangle measuring 13 inches times 12 inches ?

taurus [48]

Answer:

156 square inches

Step-by-step explanation:

We are given the two quantities

Let

length = l = 13 inches

and

Width = w = 12 inches

The formula for the area of rectangle is:

$Area=l*w$

where l is length and w is width

Putting the values of both that are given

$Area = 13*12\\=156$

so the area is 156 square inches ..

6 0

3 years ago

How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50

Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of $\frac{5}{6}$ kilogram of candy is $7.5

- We need to find the cost of $4\frac{5}{7}$ kilogram

We can use the ratio to find the answer

======= Dollar : Kilogram

======= 7.5 : $\frac{5}{6}$

======= c : $4\frac{5}{7}$

By using cross multiplication

∴ c × $\frac{5}{6}$ = 7.5 × $4\frac{5}{7}$

∵ $4\frac{5}{7}$ = $\frac{4*7+5}{7}$

∴ $4\frac{5}{7}$ = $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = 7.5 × $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = $\frac{495}{14}$

Divide both sides by $\frac{5}{6}$

∴ c = $\frac{495}{14}$ ÷ $\frac{5}{6}$

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = $\frac{495}{14}$ × $\frac{6}{5}$

∴ c = $\frac{297}{7}$ = 42.43 dollars

∵ c represents the cost of $4\frac{5}{7}$ kg

∴ It costs $42.43

7 0

3 years ago

Find the quotient −40÷20.

sukhopar [10]

Answer:

-2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Determine the total surface area for the composite figure.

Vikentia [17]

Answer:

Step-by-step explanation:

9*21*2+18*9*2+21*18+35*20+(35*20-21*18)+35*15*2+15*20*2

= 378 + 324+ 378 + 700 + 700 - 378 + 1050 + 600

= 3752

8 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago