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3 years ago

The measures of the angles of a triangle are shown in the figure below. Find the measure of the smallest angle.

Mathematics

2 answers:

Aliun [14]3 years ago

7 0

^^ that’s correct btw

nataly862011 [7]3 years ago

4 0

Answer:

(2x+18) degrees

Step-by-step explanation:

A triangle is a total of 180 degrees, so you would do:

(2x+18)+55+(4x+11)=180

(2x+4x)+(18+55+11)=180 <- take out parentheses and add like terms

6x+84=180 <- subtract 84 from both sides of the equation

6x=96 <- divide 6 from each side

x=16

Now that you know what x is you would plug it into each of the angles

Angle 1: 2x+18 --> 2(16)+18= 32+18= 50

Angle 2: 55

Angle 3: 4x+11 --> 4(16)+18= 64+18= 82

Then out of these three angles of the triangle, angle 1 (2x+18) would be the smallest.

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(

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Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

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3 years ago