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AleksandrR [38]
3 years ago
11

At noon, train A leaves Bridgton heading

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

I'd say maybe by 5:30 b would

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Calculus 3 chapter 16​
o-na [289]

Evaluate \vec F at \vec r :

\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k

Compute the line element d\vec r :

d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt

Simplifying the integrand, we have

\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt

Then the line integral evaluates to

\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}

3 0
1 year ago
There are a lot of chickens and sheep in uncle Ben`s Farm, but he sadly forget how many he has now. Only thing he remembers, the
Jobisdone [24]
C+s=48
2c+4s=134  ⇒ c+2s=67

subtracting the equations, we get, s=67-48=19,
so, c=48-19=29
7 0
3 years ago
Read 2 more answers
Write an equation of the line passing through point P(4, -6) that is perpindicular to the line y= -3.​
FinnZ [79.3K]

Answer: y=1/3x - 22/3

Step-by-step explanation:

6 0
3 years ago
Write in exponential notation
r-ruslan [8.4K]

Answer:

12^5

Step-by-step explanation:

12^5 means 12*12*12*12*12 (5 twelves)

6 0
3 years ago
This box is 3/4 inch long, 1/2 inch wide, and 3/4 inch deep. What is the volume of the box? i​
satela [25.4K]

Answer:

8/4 or just 2

Step-by-step explanation:

3/4 + 1/2 + 3/4 = 4/8

but 4/8 simplified get you 2

3 0
3 years ago
Read 2 more answers
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