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professor190 [17]
2 years ago
10

BESTIES I NEED ANSWERES TO MY MATH QUATSIONS DDD: (・_・ヾ

Mathematics
1 answer:
igomit [66]2 years ago
8 0

Answer:

hi

Step-by-step explanation:

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In order for a gear to work in a piece of machinery, the radius of the gear, r, must be greater than 4 cm, but not exceed 4.1 cm
Arturiano [62]
I’m pretty sure it’s 4 < r < 4.1
Please comment if you have any questions.
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3 years ago
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How do I solve and graph this?
lianna [129]
3x -y ⩾ 6

3x - 6 ⩾ y

now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".

if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,

3(4) - 0 ⩾ 6

12 - 0 ⩾ 6

12 ⩾ 6   

is 12 really greater or equals to 6?  well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.

now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.

check the picture below.

3 0
3 years ago
Xbnm,dfghjkihgfdsadfghjkhgfdsfghjkhgfd
ikadub [295]

Answer:

i agree :)

Step-by-step explanation:

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7 0
3 years ago
How do I find the ratio for this question?
faust18 [17]
The ratio for questions number 2 is C aka 3 to 5
4 0
3 years ago
Solve the equation : <br><img src="https://tex.z-dn.net/?f=%20%5Ccos%28x%29%20-%20%20%5Csin%28x%29%20%20%3D%20%20%5Csqrt%7B2%20%
Debora [2.8K]

Answer:

General solution is

 x = n \pi + \frac{\pi }{8}

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  cos x - sin x = √2 cos (3 x)

Dividing '√2' on both sides , we get

\frac{1}{\sqrt{2} } cos (x) - \frac{1}{\sqrt{2} } sin (x) = \frac{\sqrt{2} cos (3 x)}{\sqrt{2} }

we will use trigonometry formulas

a) Cos ( A + B) = Cos A Cos B - sin A sin B

b)  cos \frac{\pi }{4} = \frac{1}{\sqrt{2} }

<u><em>Step(ii):-</em></u>

<u><em></em></u>\frac{1}{\sqrt{2} } cos (x) - \frac{1}{\sqrt{2} } sin (x) = \frac{\sqrt{2} cos (3 x)}{\sqrt{2} }<u><em></em></u>

cos (\frac{\pi }{4} ) cos x - sin(\frac{\pi }{4} ) sin x = cos 3x

cos (\frac{\pi }{4}+x ) = cos 3 x

<u><em>Step(iii):-</em></u>

<u><em>General solution of  cos x = cos ∝  is  x = 2 nπ+∝</em></u>

<u><em>we have </em></u> cos (\frac{\pi }{4}+x ) = cos 3 x

The general solution of  cos (\frac{\pi }{4}+x ) = cos 3 x is

⇒  3 x   = 2 n \pi  + (\frac{\pi }{4}+x )

⇒ 3 x- x = 2 n \pi + \frac{\pi }{4}

 2x = 2 n \pi + \frac{\pi }{4}

<em><u>final answer</u></em>:-

General solution is

 x = n \pi + \frac{\pi }{8}

             

8 0
3 years ago
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