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ZanzabumX [31]
3 years ago
9

Assessment started: undefined.

Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

549,000

Step-by-step explanation:

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allyson can pay for her gym membership on a monthly basis, but if she pays for an entire years membership in advance, she'll rec
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Volgvan
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3 years ago
Find the derivative of the function.<br> g(x)=∫5x4xu2−1u2+1 du.
Helga [31]

Answer:

g'(x) =  \dfrac{5 *(25x^2-1)}{(25x^2+1)}- \dfrac{4 * (16x^2-1)}{(16x^2+1)}

Step-by-step explanation:

Given that:

g(x) = \int^{5x}_{4x} \dfrac{u^2-1}{u^2+1} \ \  du

Then: the derivative of the function is as follows:

g'(x) = \dfrac{(5x)^2-1}{(5x)^2+1}  \ \  \dfrac{d}{dx}(5x) -\dfrac{(4x)^2-1}{(4x)^2+1} \ \  \dfrac{d}{dx}(4x)

g'(x) =  \dfrac{5 *(25x^2-1)}{(25x^2+1)}- \dfrac{4 * (16x^2-1)}{(16x^2+1)}

6 0
4 years ago
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