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AveGali [126]
3 years ago
14

Find the value of x

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0

Answer:

<em>x=3</em>

Step-by-step explanation:

<u>Angles and Lines</u>

We must recall:

  • The sum of the internal angles of a triangle is 180°
  • Two linear angles add up to 180°

The image shows a triangle and the extension of its base to form two linear angles.

Note from the triangle, angle R is what it takes to get to 180°:

m\angle R=180-25x-(57+x)

From the line SQ, angle R what it takes to get to 180°. Thus:

m\angle R=180-45x

Equating:

180-25x-(57+x)=180-45x

Subtracting 180 and simplifying:

-25x-57-x=-45x

19x=57

Dividing by 19:

x=3

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PLS HELP ME!!!!!!!!! I WILL MARK YOU!!!!!
Nikitich [7]

Answer:

7.92

Step-by-step explanation:

Given

c² + 0.1c - 24 ← substitute c = - 5.7 into the expression

= (- 5.7)² + 0.1(- 5.7) - 24

= 32.49 - 0.57 - 24

= 31.92 - 24

= 7.92

4 0
3 years ago
Rename 28 percent as a decimal and fraction in its simplest form.
VARVARA [1.3K]
28% is 28/100 as a fraction but the simplest form is 14/50 and it can be simplified to 7/25. the decimal is 0.28

fraction is 7/25
decimal is 0.28

7 0
3 years ago
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(x + 5)2 + (y - 7)2 = 36, its radius is
sashaice [31]
6 because the 36 is r² where r is the radius, r² = 36; we have to isolate the r so it's by its self, so square root both sides, r = 6 
5 0
3 years ago
If s store is selling boxes of pudding at 3 for $0.99,how much would 12 boxes cost
sweet [91]

Answer:

The cost price of 12 boxes of pudding is $3.96

Step-by-step explanation:

Given as :

The quantity of pudding boxes = 3

The cost price for 3 boxes = $0.99

Again ,

The quantity of pudding boxes = 12

Let The cost price for 12 boxes = $x

Now, According to question

<u>Using Unitary method</u>

∵ The cost price of 3 boxes of pudding = $0.99

or,The cost price of 1 boxes of pudding = \dfrac{0.99}{3} = $0.33

∴The cost price of 12 boxes of pudding =$0.33 × 12

I.e x =$3.96

So,The cost price of 12 boxes of pudding = x =$3.96

Hence,The cost price of 12 boxes of pudding is $3.96 Answer

4 0
3 years ago
Greatest common factor of 4ax^2+4ax+4a
Rina8888 [55]

Simplifying

4AX2 + 4AX + 4A = 0

Reorder the terms:

4A + 4AX + 4AX2 = 0

Solving

4A + 4AX + 4AX2 = 0

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), '4A'.

4A(1 + X + X2) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'A' equal to zero and attempt to solve:

Simplifying

A = 0

Solving

A = 0

Move all terms containing A to the left, all other terms to the right.

Simplifying

A = 0

Subproblem 2

Set the factor '(1 + X + X2)' equal to zero and attempt to solve:

Simplifying

1 + X + X2 = 0

Solving

1 + X + X2 = 0

Move all terms containing A to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + X + -1 + X2 = 0 + -1

Reorder the terms:

1 + -1 + X + X2 = 0 + -1

Combine like terms: 1 + -1 = 0

0 + X + X2 = 0 + -1

X + X2 = 0 + -1

Combine like terms: 0 + -1 = -1

X + X2 = -1

Add '-1X' to each side of the equation.

X + -1X + X2 = -1 + -1X

Combine like terms: X + -1X = 0

0 + X2 = -1 + -1X

X2 = -1 + -1X

Add '-1X2' to each side of the equation.

X2 + -1X2 = -1 + -1X + -1X2

Combine like terms: X2 + -1X2 = 0

0 = -1 + -1X + -1X2

Simplifying

0 = -1 + -1X + -1X2

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Solution

A = {0}

3 0
3 years ago
Read 2 more answers
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