All categories

3 years ago

2 +2 =4 -2+3-1+2-4= whats the anwser

Mathematics

2 answers:

Sphinxa [80]3 years ago

7 0

This equation does not exist because 4 does not equal 2

vova2212 [387]3 years ago

5 0

Answer:

Step-by-step explanation:

4-2=2

2+3=5

5-1=4

4+2=6

6-4=2

You might be interested in

Can someone help me solve this?

atroni [7]

Answer:

Step-by-step explanation:

speed=d÷t.

s=1/4=1/20

cross multiply your equation

6 0

1 year ago

There were 26 students in the classroom. 14 of the students went to the cafeteria and the rest went to the gym. What percentage

OverLord2011 [107]

Answer:

About 53% percent of the students went to the cafeteria.

Step-by-step explanation:

there are 26 students and 14 left that can be put into the fraction 14/26.

To find the percentage you then divide 14 by 26 and turn it into a percent and you get something like 53.846... but you can simplify it to 53%

8 0

2 years ago

Read 2 more answers

A company makes 100 bags. 32 of the bags have buttons but no zips. 32 of the bags have zips but no buttons. 35 of the bags have

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

6 0

2 years ago

Are the quadrilaterals similar? If so, give the scale factor. If not, explain.

castortr0y [4]

These are not similar. For them to be similar, they need to exist in proportion to each other for every single side. The ratio of the 12:9 sides is 4:3 when reduced. The ratio of the other 2 sides is 5:3. They all have to have the same ratio for them to be similar.

7 0

2 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago