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3 years ago

An electric motor operates a pump that irri-

Physics

1 answer:

PolarNik [594]3 years ago

7 0

Answer:

a. 5A

b. 39.60%

Explanation:

The computation is shown below:

a. The current does it draw is

= v ÷ R

= 110v ÷ 22

= 5A

b. Now the efficiency of the motor is

n = mgh ÷ vlt

= (10,000 × 9.8 × 8) ÷ (5 × 3600 × 110)

= 784000 J ÷ 1,980,000

= 39.60%

hence, the above formulas are applied & the same is relevant

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A 68.2 kg base runner begins his slide into second base while moving at a speed of 4.33 m/s. He slides so that his speed is zero

qwelly [4]

Answer:

$147.653J = W_f$

Explanation:

We know that:

$E_i - E_f = W_f$

where $E_i$ is the initial energy, $E_f$ is the final energy and $W_f$ is the energy lost due to friction.

so:

$\frac{1}{2}MV^2-0 = W_f$

Where M is the mass and V is the velocity of the runner, so:

$\frac{1}{2}(68.2kg)(4.33m/s)^2 = W_f$

$147.653J = W_f$

7 0

4 years ago

Define pressure. write it's Si unit.<br>

tekilochka [14]

Hi :)

Pressure is the force applied perpendicular to the surface of an object per unit area

The SI unit of pressure is N/m^2

Hope this helps!

8 0

3 years ago

Read 2 more answers

If you swim with the current in a river, your speed is increased by the speed of the water; if you swim against the current, you

Blababa [14]

Answer:

11.23%

Explanation:

Lets take

Speed of man in still water =u= 1.73 m/s

Speed of flow of water = v=0.52 m/s

When swims in downward direction then speed of man = u + v

When swims in upward direction then speed of man = u - v

Lets time taken by man when he swims in downward direction is $t_1$ and when he swims in downward direction is $t_2$

Lets distance is d and it will be remain constant in both the case

$d=(u+v)t_1$

$d=(u-v)t_2$

$(1.73+0.52)t_1=(1.73-0.52)t_2$

$t_2=1.85t_1$

Time taken in still water

2 d= t x 1.73

t=1.15 x d sec

$t_1=0.44d\ sec$

$t_2=0.82d\ sec$

total time in current = 0.82 +0.44 d=1.26 d sec

So the percentage time

$percentage\ time =\dfrac{1.28-1.15}{1.15}$

Percentage time =11.32%

So it will take 11.32% more time as compare to still current.

5 0

3 years ago

The SI system uses three base units. Question 6 options: True False

GalinKa [24]

Answer:

The answer is false

Explanation:

Though the mostly used SI unit of measurement or the most popular units are the

Length,

Time and

Mass

i.e meter (m), seconds (s), kilogram (kg)

Aside all the above stated units for measurements there are other four basic units which are itemized bellow.

they are

1. Amount of substance - mole (mole)

2. Electric current - ampere (A)

3. Temperature - kelvin (K)

4. Luminous intensity - candela (cd)

6 0

4 years ago

A car of mass 1000.0 kg is traveling along a level road at 100.0 km/h when its brakes are applied. Calculate the stopping distan

OleMash [197]

Explanation:

It is given that,

Mass of the car, m = 1000 kg

Speed of the car, v = 100 km/h = 27.77 m/s

The coefficient of kinetic friction of the tires, $\mu_k=0.5$

Let f is the net force acting on the body due to frictional force, such that,

$-f=ma$

$a=\dfrac{-f}{m}$

$a=\dfrac{-\mu _k mg}{m}$

$a=\mu_k g$

$a=-0.5\times 9.8$

$a=-4.9\ m/s^2$

We know that the acceleration of the car in calculus is given by :

$v.dv=a.dx$ , x is the stopping distance

$\int\limits^0_v {v.dv}=\int\limits^x_0 {a.dx}$

$\dfrac{v^2}{2}|_v^0=ax$

$0-(27.77)^2=-2\times 4.9x$

On solving the above equation, we get, x = 78.69 meters

So, the stopping distance for the car is 78.69 meters. Hence, this is the required solution.

6 0

3 years ago