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nordsb [41]
2 years ago
9

Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​

Mathematics
1 answer:
tekilochka [14]2 years ago
3 0

Step-by-step explanation:

\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2}  }{sinA(1+cosA)} \\\\

\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\ and we have sin^{2}+cos^{2} =1

so \frac{1+1+2cosA  }{sinA(1+cosA)} \\\\

\frac{2+2cosA  }{sinA(1+cosA)} \\\\

\frac{2(1+cosA)}{sinA(1+cosA)} \\\\

\frac{2}{sinA} we have \frac{1}{sin}=cosec\\

<em>Finally </em>2cosecA<em />

<em>I really hope this helps coz it took much time </em>

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MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

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Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB = \sqrt{(0-6)^2+(6-5)^2} = \sqrt{37}

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Perimeter = \sqrt{37}+\sqrt{37}+\sqrt{74}

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