If you use FOIL to multiply these two brackets, it will lead you what is exactly written (xa+xb+ya+yb)
so it is correct
A
For this case we have the following expression:
8 + 0 = 8
The sum has several properties.
One of them is the following one:
Neutral element: the sum has a neutral element that is 0. If you add 0 to any number the result is the same number.
Answer:
The property shown in the given expression is:
Neutral element.
Si you would subtract 6x from both sides so you would have 9y=1500-6x. Then you would divide both sides by 9 and get y=166.66-6/9x. The -6/9x can be reduced to -2/3x and that is your slope or your
rise/run and the only graph that show this is the second one
Given that <span>Line m is parallel to line n.
We prove that 1 is supplementary to 3 as follows:
![\begin{tabular} {|c|c|} Statement&Reason\\[1ex] Line m is parallel to line n&Given\\ \angle1\cong\angle2&Corresponding angles\\ m\angle1=m\angle2&Deifinition of Congruent angles\\ \angle2\ and\ \angle3\ form\ a\ linear\ pair&Adjacent angles on a straight line\\ \angle2\ is\ supplementary\ to\ \angle3&Deifinition of linear pair\\ m\angle2+m\angle3=180^o&Deifinition of supplementary \angle s\\ m\angle1+m\angle3=180^o&Substitution Property \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AStatement%26Reason%5C%5C%5B1ex%5D%0ALine%20m%20is%20parallel%20to%20line%20n%26Given%5C%5C%0A%5Cangle1%5Ccong%5Cangle2%26Corresponding%20angles%5C%5C%0Am%5Cangle1%3Dm%5Cangle2%26Deifinition%20of%20Congruent%20angles%5C%5C%0A%5Cangle2%5C%20and%5C%20%5Cangle3%5C%20form%5C%20a%5C%20linear%5C%20pair%26Adjacent%20angles%20on%20a%20straight%20line%5C%5C%0A%5Cangle2%5C%20is%5C%20supplementary%5C%20to%5C%20%5Cangle3%26Deifinition%20of%20linear%20pair%5C%5C%0Am%5Cangle2%2Bm%5Cangle3%3D180%5Eo%26Deifinition%20of%20supplementary%20%5Cangle%20s%5C%5C%0Am%5Cangle1%2Bm%5Cangle3%3D180%5Eo%26Substitution%20Property%0A%5Cend%7Btabular%7D)
</span>
Answer:
Yes, it is
Step-by-step explanation:
Given
The attached image
Required
Is AB a tangent to the circle
From the attached circle, we can see that AP is the radius of the circle P.
And by definition, a tangent touches the circle at only one point.
Since AB touches the circle at only point A, then AB is a tangent.
