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Margaret [11]
2 years ago
13

What are the values of h and x in the right triangle? Explain.

Mathematics
1 answer:
alexandr402 [8]2 years ago
3 0

Answer:

h = 60 ; x = 25

Step-by-step explanation:

You are going to want to use Pythagorean Theorem to solve these.

Pythagorean Theorem: a² + b² = c²

h² + 144² = 156²

h² + 20736 = 24336

h² = 3600

h = 60

x² + 60² = 65²

x² + 3600 = 4225

x² = 625

x = 25

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aivan3 [116]

Answer: 5+10=15

Step-by-step explanation:

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3 years ago
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​3 ​/​10 ​​ = ​9 /​k ​​ what is k
NemiM [27]
In order to isolate k, we would first cross multiply
3*k=9*10
3k=90

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K=30

Hope this helps
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Which weights more 2.48 or 2.5​
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an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.​
dolphi86 [110]

Answer:

\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We need a length of a height.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=5,\ leg=h,\ hypotenuse=20

Substitute:

5^2+h^2=20^2

25+h^2=400             <em>subtract 25 from both sides</em>

h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm

Calculate the area:

A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2

8 0
3 years ago
Question 13. Please
Sonbull [250]

Answer:

d

Step-by-step explanation:

Δ OPG is right with hypotenuse OG being the radius of the circle

Using Pythagoras' identity in the right triangle

OG² = OP² + PG²

[ PG = 11 , since OP is the perpendicular bisector of FG ]

OG² = 8² + 11² = 64 + 121 = 185

Δ OQS is right with hypotenuse OS being the radius

Using Pythagoras' identity

OS² = QS² + OQ² , that is

185 = 13² + x²

185 = 169 + x² ( subtract 169 from both sides )

16 = x² ( take the square root of both sides )

4 = x → d

8 0
2 years ago
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