Carlos made the mistake that he did not combine like terms (3 x and 2 x) properly and did not use addition property of equality.
<u>Step-by-step explanation:</u>
Carlos did the work as 3 x + 2 x - 6 = 24
We need to find his mistake that he made in above given.
Here, he did not add the like terms (3 x and 2 x)
3 x + 2 x = 5 x
Therefore, his work should be
5 x - 6 = 24
Also, he did not use addition property of equality. It means the equation remains same even though the same number gets added on both sides. It would be
5 x - 6 = 24
+ 6 = + 6
-----------------------
5 x = 30
Dividing 30 by 5, we get answer as '6'. Hence,
= 6
So, stated the above two are the mistakes found in carlos work.
Answer:
65 3 46
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let M ( 9 , -5 ) be ( x₁ , y₁ ) and N ( - 11 , 10 ) be ( x₂ , y₂ )
<u>Finding</u><u> </u><u>the </u><u>distance </u><u>between</u><u> </u><u>these</u><u> </u><u>points</u>
Hope I helped!
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Solve for x by simplifying both sides of the equation, then isolating the variable
x is equal to y/12
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Mean (m) = 72
Standard deviation (sd) = 10
Grading cutoff policy:
bottom 5% receive F
next 15% receive D
next 35% receive C
next 30% receive B
A) Give the cutoffs for the grades in this course in terms of standardized scores.
Standardized score for grade cutoff:
Locating the Zscore for the proportions on the z table :
Bottom 5% = 0.05 ; corresponding Zscore = - 1.645
next 15% receive D = (5 +15)% 0.20 ; corresponding Zscore = - 0.84
next 35% receive C = (20+35)% = 0.55 ; corresponding Zscore = 0.13
next 30% receive B = (55 + 30)% = 0.85 ; Corresponding Zscore = 1.04
B) Give the cutoffs in terms of actual total scores.
Recall:
Zscore = (x - m) /sd ; where x = actual score
x = sd*z + m
For F:
10*(-1.645) + 72 = 55.55
For D:
10*(-0.84) + 72 = 63.6
For C:
10*(0.13) + 72 = 73.3
For B:
10*(1.04) + 72 = 82.4
C) Do you think that this method of assigning grades is a good one?
Yes, it is good in terms of expressing scores around the mean such that score below are negative and those above are positive. However, it is a little bit ambiguous.
