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ankoles [38]
3 years ago
15

WILL MARK BRAINLIEST PROBABILITY!!

Mathematics
1 answer:
Margarita [4]3 years ago
8 0

Answer:5/22

Step-by-step explanation:1/2+1/4+5(total-1 pink)=11/2

probability of getting purple=5/11/2,5/11*1/2=5/22

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You noticed that $750 was stolen from your checking account using your debit card, but life being as busy as it is, you didn't r
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Answer:

The answer is: full liability for unauthorized debit charges

Explanation:

Once you discover that an amount of money was stolen from your debit card account, it is important to report it immediately to the card issuer. This will prevent "liability for unauthorized debit charges on your end." Each type of card that you avail has a set of rules when it comes to the <em>card owner's duties and liabilities. </em>

You have to tell your card issuer, either by<em> writing or by phone.</em> This should be done within 60 days from the time you encountered the issue. This will allow you to dispute any unauthorized charges. However, the sooner you report, the better it will be so you won't incur any liabilities.

So, in the case above, you didn't report the fraudulent activity until 75 days. This gives you a <u>"full liability for unauthorized debit charges."</u>

Thus, this explains the answer.

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3 years ago
Jocelyn walks her dog 5 days each week.Each Walk is 2 1/4 miles long. What is the total number of miles that Jocelyn walks her d
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Answer:the answer is c

Step-by-step explanation:

6 0
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Read 2 more answers
17.381 divided by 1.21​
daser333 [38]

Answer:

14.36446281 is the answer, you probably have to round

7 0
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Evaluate the integral ∫2−1|x−1|dx
defon

I think you might be referring to the definite integral,

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx

Recall the definition of absolute value:

|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

Then |x-1|=x-1 if x\ge1, and |x-1|=1-x is x. So spliting up the integral at <em>x</em> = 1, we have

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx

The rest is simple:

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}

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3 years ago
Given: BC ≅ CD and AC bisects ∠BCD
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Go download Conects. You gonna love it.
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