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kondaur [170]
3 years ago
9

Solve five ninths minus two sixths equals blank.

Mathematics
1 answer:
zimovet [89]3 years ago
4 0

Answer:11/50

Step-by-step explanation:

i dont really know.

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The Value of the 7 in 507,264 is ten times e value of the 7 in witch number?
mestny [16]
The answer is A
the answer is A


700 
what i did was i divided 7000 by 10 and i  got 700. then to check, i multiplied 700 by 10 and got 7000


4 0
3 years ago
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Which is the best first step and explanation for solving this system of equations?
Volgvan

Answer:

x=-4/9, y=10/3. (-4/9, 10/3).

Step-by-step explanation:

3x+4y=12

3x=2y-8

--------------

2y-8+4y=12

6y-8=12

6y=12+8

6y=20

y=20/6

simplify,

y=10/3

3x=2(10/3)-8

3x=20/3-8

3x=20/3-24/3

3x=-4/3

x=(-4/3)/3

x=(-4/3)(1/3)=-4/9

x=-4/9, y=10/3. (-4/9, 10/3).

7 0
3 years ago
If x= 1/2-√3 , prove that x³-2x²-7x+5=3
prohojiy [21]
x=\frac{1}{2}-\sqrt3\\\\x^3-2x^2-7x+5=3\\\\(\frac{1}{2}-\sqrt3)^3-2(\frac{1}{2}-\sqrt3)^2-7(\frac{1}{2}-\sqrt3)+5\\\\=(\frac{1}{2})^3-3\cdot(\frac{1}{2})^2\cdto\sqrt3+3\cdot\frac{1}{2}\cdot(\sqrt3)^2-(\sqrt3)^3-...\\\\...-2[(\frac{1}{2})^2-2\cdot\frac{1}{2}\cdot\sqrt3+(\sqrt3)^2]-\frac{7}{2}+7\sqrt3+5

=\frac{1}{8}-\frac{3\sqrt3}{4}+\frac{9}{2}-3\sqrt3-2(\frac{1}{4}-\sqrt3+3)-\frac{7}{2}+7\sqrt3+5\\\\=\frac{1}{8}+\frac{9}{2}-\frac{1}{2}-6-\frac{7}{2}+5-\frac{3}{4}\sqrt3-3\sqrt3+2\sqrt3+7\sqrt3\\\\=\frac{1}{8}+\frac{1}{2}-1+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{1}{2}+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{4}{8}+5\frac{1}{4}\sqrt3\\\\=-\frac{3}{8}+5\frac{1}{4}\sqrt3\neq3
6 0
3 years ago
Simplify the following expression 4w x 3w x 2y x 2y
Anestetic [448]

Answer:

48w^2y^2

I used a simplify calculator I hope this is correct.

4 0
3 years ago
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What type of decimal is this fraction: LaTeX: \frac{11}{20}
skad [1K]

11/20

Divide 11 by 20 to find the decimal value.

11/20 = 0.55

The decimal only contains two numbers, so it is a terminating fraction.

6 0
3 years ago
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