Help me help me please

During the early years of Earth, lighter elements such as silicon, magnesium, and aluminum rose to the surface, forming Earth’s

CaHeK987 [17]

Answer:

TRUE

Explanation:

The earth is comprised of three distinct layers namely the core, mantle and the crust. The core is the extreme interior layer which is comprised of the denser elements like iron, nickel and other siderophile elements. Thee denser minerals are deposited, by sinking into the core of the earth forming the highest density layer. The core was formed about 1 to 1.5 billion years back.

Whereas, the least dense elements were concentrated in the upper region of the earth forming the crust. These are the lighter elements so it did not get sink into the bottom. But still many of these elements are found in association with the core rocks. There occurred constant evolution on the crustal portion of the earth.

Thus, these elements are found in larger proportions in the crust and were formed during the initial formation of the earth.

Hence, the above-given statement is True.

5 0

3 years ago

What was the arms act?

nata0808 [166]

Arms act, arms act, arms act, arms act, arms act, arms act, arms act, arms act

5 0

2 years ago

Como se relaciona la geografía con otras ciencias?

shtirl [24]

Answer:

¿Qué aporta, principalmente, la Geografía a las demás ciencias con las que comparte campo de estudio? Aporta el estudio de la distribución espacial de los fenómenos que se estudian. Aporta una visión de conjunto de lo que piensan todas las ciencias sobre el fenómeno que se está estudiando

6 0

3 years ago

6. What is the approximate volume of a cube where all sides are equal to 2.5 cm?

erica [24]

Answer:

Hi, There! I'm here to Help!

What is the approximate volume of a cube where all sides are equal to 2.5 cm?

c. 15.6 cm3 is the Correct Answer!

Explanation: Below We Have the Formula!

V= a3 = 2.53 = 15.625cm³

4 0

3 years ago

Please answer this fast and here only

Vaselesa [24]

Answer:

1) a) $r_{R,I} = 1150\,m$ , b) $r_{R,II} = 3400\,m$ , c) $r_{R,III} = 2750\,m$ .

2) a) $r_{R,I} = 45,2\,km$ , b) $r_{R, II} = 28,15\,km$ , c) $r_{R,III} = 51,8\,km$ .

Explanation:

The scale factor is defined by the following expression:

$n = \frac{r_{S}}{r_{R}}$ (1)

Where:

$n$ - Scale factor.

$r_{S}$ - Scale distance, in centimetres.

$r_{R}$ - Real distance, in centimetres.

1) If we know that $n = \frac{1}{50000}$ , $r_{S,I} = 2,3\,cm$ , $r_{S,II} = 6,8\,cm$ and $r_{S,III} = 5,5\,cm$ , then the actual distances in metres are:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }$

$r_{R,I} = 115000\,cm$

$r_{R,I} = 1150\,m$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }$

$r_{R,II} = 340000\,cm$

$r_{R,II} = 3400\,m$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }$

$r_{R,III} = 275000\,cm$

$r_{R,III} = 2750\,m$

2) If we know that $n = \frac{1}{50000}$ , $r_{S, I} = 90,4\,cm$ , $r_{S, II} = 56,3\,cm$ and $r_{S,III} = 103,6\,cm$ , then the actual distance in kilometres is: