It's true
There are thousands of combinations that can be put together to form a all sorts of compounds. That's the whole basis of inorganic chemistry. Organic chemistry is a little bit different. It is more restricted.
Answer:
si es un país democrático.
justificación: el estado colombiano es una democracia sólida y fuerte, con gran tradición dentro de la región, esta tiene como eje principal la generación de empleo, buscando que todos los colombianos tengan ingresos seguros un trabajo digno y pertenezca a la seguridad social.
Explanation:
esperó te sirva
Answer: The volume of the balloon at the center of the typhoon is 41.7L.
Note: The complete question is given below;
If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center?
The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr.
Explanation:
Since no temperature changes were given, it is assumed to be constant. Therefore, Boyle's law which describes the relationship between pressure and volume is used to determine the new volume at the center of Typhoon Odessa. Mathematically, Boyle's law states that; P1V1 = P2V2
Assuming 1atm = 1 bar, 1mbar = 0.001atm, 40mbar = 0.040atm
P1 = 1.0atm, V1 = 40.0L, P2 = 1atm - 0.040atm = 0.960atm, V2 = ?
Using P1V1 = P2V2
V2 = P1V1/P2
V2 = 1.0 * 40.0 / 0.96
V2 = 41.67L
Therefore, the volume of the balloon at the center of the typhoon is 41.7L.
V = maximum capacity of human lung = 3 liter = 3 x 0.001 m³ = 0.003 m³ (Since 1 liter = 0.001 m³)
P = pressure of oxygen = 21.1 kilo pascal = 21.1 x 1000 = 21100 Pa (since 1 kilo = 1000)
T = temperature of air = 295 K
n = number of moles of oxygen
Using the ideal gas equation
PV = n RT
inserting the above values in the equation
(21100) (0.003) = n (8.314) (295)
n = 0.026 moles
