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kozerog [31]
3 years ago
11

How would you prepare 1 liter of .030 m copper 2 sulfate pentahydrate?

Chemistry
1 answer:
Ierofanga [76]3 years ago
5 0
Answer is: dissolve 74,9 grams CuSO₄·5H₂O in one liter volumetric flask.
V(CuSO₄·5H₂O) = 1 L.
c(CuSO₄·5H₂O) = 0,30 mol/L.
n(CuSO₄·5H₂O)  = V(CuSO₄·5H₂O) · c(CuSO₄·5H₂O) .
n(CuSO₄·5H₂O) = 1 L · 0,3 mol/L.
n(CuSO₄·5H₂O) = 0,3 mol.
m(CuSO₄·5H₂O) = n(CuSO₄·5H₂O) · M(CuSO₄·5H₂O).
m(CuSO₄·5H₂O) = 0,3 mol · 249,7 g/mol.
m(CuSO₄·5H₂O) = 74,9 g.
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There are four substances, A, B C and D. A and C are pure substances. They cannot be broken down into anything simpler by chemic
yarga [219]

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6 0
3 years ago
Which factor impacts the possible number of ways in which different atoms can be put together?
kumpel [21]
D is just straight up false, if I were to take a stab at it, the only one that’s seems logical to me B. “The ability of atoms to combine in unlimited ways”
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3 years ago
A container holds 100.0 mL of nitrogen at 21° C and a pressure of 736 mm Hg. What will be its volume if the temperature increase
devlian [24]

Answer:

V₂ = 104.76 mL

Explanation:

Given data:

Initial volume = 100.0 mL

Initial temperature = 21°C (21 + 273.15 K = 294.15 K)

Final temperature = 35°C (35 + 273.15 K = 308.15 k)

Final volume = ?

Solution:

Charles Law:

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

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T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ =100.0 mL × 308.15 K / 294.15 K

V₂ = 30815 mL.K /294.15 K

V₂ = 104.76 mL

5 0
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Mass of a mole is known as
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Answer:

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Explanation:

Could I have branliest , heart, and 5 stars

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3 years ago
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