Answer:

Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is equal
In this problem Triangles OQP and OQ'P' are similar by AA Similarity Postulate
so

we have


substitute

<span>0.05 arc-second = 1 degree/72000 = (pi
radians)/(180*72000) = 2.424 x 10^(-7) radians</span>
<span>The distance is roughly: </span>
<span>R*(theta) = (600 light-years)*2.424 x 10^(-7) = 0.00014544 light-years = 1.275
light-hours = (3600 seconds)*(3 x 10^8 m/s)*(1.275) = 1.38 x 10^12 meters.</span>
Answer:
11309.7 cm
Step-by-step explanation:
Volume = πr^2h
= π×20^2×9
= 3600π
= 11309.733552923
=11309.7 cm