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3 years ago

Apply the distributive property to factor out the greatest common factor. 14e - 27f =

1 answer:

3 0

The factors of 14 are 2 and 7. The factors of 27 are 3 and 9. So we can put those into an expression. I have absolutely no idea how to explain it in words, so imma just show you.

14e-27f

e(2x7)-e(9x3)

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hope it helps

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Which triangle(s) are similar to ABC?

Harlamova29_29 [7]

Triangle MNP

Sorry if I’m wrong but I think that’s the one

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3 years ago

Identify the solution to the following inequality: -1/2 (x+3) > x - 3

mrs_skeptik [129]

Answer:

Step-by-step explanation:

- $\frac{1}{2}$ (x + 3) > x - 3 ( multiply both sides by 2 to clear the fraction )

- (x + 3) > 2x - 6 ← distribute parenthesis on left side by - 1

- x - 3 > 2x - 6 ( subtract 2x from both sides )

- 3x - 3 > - 6 ( add 3 to both sides )

- 3x > - 3

divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity

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2 years ago

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Consider a drug testing company that provides a test for marijuana usage. Among 317 tested subjects, results from 25 subjects w

svet-max [94.6K]

Answer:

We conclude that we fail to reject $H_0$ as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

Step-by-step explanation:

We are given that among 317 tested subjects, results from 25 subjects were wrong.

We have to test the claim that less than 10 percent of the test results are wrong.

Let p = proportion of subjects that were wrong.

So, Null Hypothesis, $H_0$ : p = 10% {means that 10 percent of the test results are wrong}

Alternate Hypothesis, $H_A$ : p < 10% {means that less than 10 percent of the test results are wrong}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p (1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of test results that were wrong = $\frac{25}{317}$ = 0.08

n = sample of tested subjects = 317

So, test statistics = $\frac{0.08-0.10}{\sqrt{\frac{0.08 (1-0.08)}{317} } }$

= -1.31

The value of z test statistics is -1.31.

Now, the P-value of the test statistics is given by the following formula;

P-value = P(Z < -1.31) = 1 - P(Z $\leq$ 1.31)

= 1 - 0.9049 = 0.095

Now, at 0.05 significance level the z table gives critical value of -1.645 for left-tailed test. Since our test statistics is more than the critical value of z as -1.31 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that we fail to reject $H_0$ as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

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3 years ago

Jasmine's dessert takes 3½ minutes to cook in the microwave.

olya-2409 [2.1K]

There are 60 seconds in one minute

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3 years ago

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The U.S. Bureau of Labor Statistics releases figures on the number of full-time wage and salary workers with flexible schedules.

Sindrei [870]

Answer:

61.70% probability that he or she will be between 23 and 52 years of age

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d is given by the following formula.

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

The numbers of full-time wage and salary workers in each age category are almost uniformly distributed by age, with ages ranging from 18 to 65 years.

This means that $a = 18, b = 65$ . So

(a) what is the probability that he or she will be between 23 and 52 years of age?

$P(23 \leq X \leq 52) = \frac{52 - 23}{65 - 18} = 0.6170$

61.70% probability that he or she will be between 23 and 52 years of age

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4 years ago