Hey!
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Solution:
= 3(-3) - (3(0) + 4(-7)²)
= -9 - (0 + 4(49))
= -9 - 196
= -205
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Answer:
-205
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Hope This Helped! Good Luck!
Answer: (b) exactly one plane contains a given line and a point not on the line.
Step-by-step explanation: The basic postulates of geometry are very-well known to all of us. For example-
(i) The intersection of two lines determines a point,
(ii) Two parallel lines give result to a plane,
(iii) A line and a point not on the line determines a plane, etc...
Thus, with the help of the third point, we can easily arrive at the conclusion that a given line and a point not lying on the line is contained in a plane. For example- see the attached figure, AB is a line and P is any point not on the line. They both contained in the plane ABC.
Hence, the correct option is (b).
It 13 because you subtract 6 from 74.25 and then divide by 5.25
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Evaluate the function at 2. That is f(2).
Evaluate the function at 0. That is f(0).
the average rate of change from 0 to 2 is (f(2) - f(0))/(2 - 0)
f(x) = 120(0.1)^x
f(2) = 120(0.1)^2 = 120 * 0.01 = 1.2
f(0) = 120(0.1)^0 = 120 * 1 = 120
average rate of change = (1.2 - 120)/(2 - 0) = -118.8/2 = -59.4