1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
The sum of the angles of a quadrilaterals is 360 so 8s=360 s=45
42 + 28 + 12 + 18 = 100 total beads
probability of not drawing a yellow or a green : (12 + 18) / 100 = 30/100 reduces to 3/10 or 30%
probability of drawing a red or green : (18 + 28) / 100 = 46/100 reduces to
23/50 or 46%