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xxMikexx [17]
4 years ago
10

I’m having trouble with this. Can someone please help me out.

Mathematics
1 answer:
Amiraneli [1.4K]4 years ago
6 0
Because the company wants to know how much PER HOUR, we go to the first unit for the first hour. We can see that if we travel up the y-axis 8 units, we get $45 per hour. 
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What number represents the same amount as 8 hundreds + 10 + 0 ones?
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Answer:

810

Step-by-step explanation:

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Please help grades are due tmr
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Which of the following best describes the Washington econonmy since World War 2
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Read 2 more answers
Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M′N′O′P′Q′.
nikdorinn [45]

The new coordinates of the dilated polygon would have coordinates at M'(1.6, 3.2) and N'(3.2, 4).

<h3>What is an equation?</h3>

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Dilation is the increase or decrease in the size of a figure by a scale factor.

Given that Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin. If point M(2, 4) and N(4, 5). The new coordinates would be at M'(1.6, 3.2) and N'(3.2, 4).

The new coordinates of the dilated polygon would have coordinates at M'(1.6, 3.2) and N'(3.2, 4).

Find out more on equation at: brainly.com/question/2972832

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3 0
2 years ago
A home security system is designed to have a 99% reliability rate. Suppose that nine homes equipped with this system experience
bulgar [2K]

Answer:

a) P(X \geq 1) = 1-P(X

P(X=0)=(9C0)(0.99)^0 (1-0.99)^{9-0}=1x10^{-18}

And replacing we got:

P(X \geq 1) =1 -1x10^{-18} \approx 1

b) P(X=7)=(9C7)(0.99)^7 (1-0.99)^{9-7}=0.003355

P(X=8)=(9C8)(0.99)^8 (1-0.99)^{9-8}=0.083047

P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517

And adding we got:

P(X \geq 7) = 0.003355+0.083047+0.913517 =0.99992

c) P(X \leq 8) =1 -P(X>8) = 1-P(X=9)

P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517

And replacing we got:

P(X \leq 8)= 1-0.913517=0.086483

Step-by-step explanation:

Let X the random variable of interest "numebr of times that an alarm is triggered", on this case we now that:

X \sim Binom(n=9, p=0.99)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

We want to find this probability:

P(X \geq 1) = 1-P(X

P(X=0)=(9C0)(0.99)^0 (1-0.99)^{9-0}=1x10^{-18}

And replacing we got:

P(X \geq 1) =1 -1x10^{-18} \approx 1

Part b

P(X \geq 7)= P(X=7) +P(X=8)+ P(X=9)

P(X=7)=(9C7)(0.99)^7 (1-0.99)^{9-7}=0.003355

P(X=8)=(9C8)(0.99)^8 (1-0.99)^{9-8}=0.083047

P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517

And adding we got:

P(X \geq 7) = 0.003355+0.083047+0.913517 =0.99992

Part c

P(X \leq 8) =1 -P(X>8) = 1-P(X=9)

P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517

And replacing we got:

P(X \leq 8)= 1-0.913517=0.086483

4 0
3 years ago
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