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Tresset [83]
3 years ago
5

Find the area under the standard normal curve that lies between z = −2.30 and z = 1.08

Mathematics
1 answer:
Vilka [71]3 years ago
5 0
The answer is C thank youu
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The bottom of a rectangular swimming pool has a perimeter of 142 meters and an area of 1,050 square meters. What are the dimensi
lubasha [3.4K]

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Step-by-step explanation:

1,129 not 100% sure but i think u add them both together

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4 years ago
Can someone please help me it would mean a lot!<br><br> 3x - 4 = 6 + x
yuradex [85]

Answer:

x=5

Step-by-step explanation:

3x-4=6+x

You want to get x by itself. So, you would subtract x from the right side, and subtract it from 3x. That gives you this:

2x-4=6

Now you would add 4 to cancel out on the left side, then add it to the 6. This gives you:

2x=10

Now divide 2 from both sides and that gives you what x equals.

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6 0
4 years ago
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Based on the given information in the figure at the right, how can you justify that (TRIANGLE SHAPE) ABC= (TRIANGLE SHAPE) CDA?
arlik [135]

Answer:

A SIRRRRRRRRRRRRR PRETTY SUREERREEERRERREREERRERERERERERERERE

Step-by-step explanation:

5 0
3 years ago
Solve the following problem. Write the complete proof in your paper homework and for online (only) complete the probing statemen
Charra [1.4K]

Answer:

OM = ON by using concurrency of Δs BOM and DON

Step-by-step explanation:

In the figure ABCD:

∵ AB // CD

∵ CB // AD

∵ In any quadrilateral If every two sides are parallel then

  it will be a parallelogram

∴ ABCD is a parallelogram

∴ AC and BD bisects each other at O ⇒ (properties of parallelogram)

∴ OD = OB ⇒ (1)

∵ BC // AD

∴ m∠CBD = m∠ADB ⇒ alternate angles

∵ M ∈ BC , N ∈ AD , O ∈ BD

∴ m∠MBO = m∠NDO ⇒ (2)

∵ BD intersects MN at O

∴ m∠MOB = m∠NOD ⇒ (3) (vertically opposite angles)

From (1) , (2) and (3)

∴ ΔBOM ≅ ΔDON

∴ OM = ON

3 0
4 years ago
Read 2 more answers
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