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Tresset [83]
3 years ago
5

Find the area under the standard normal curve that lies between z = −2.30 and z = 1.08

Mathematics
1 answer:
Vilka [71]3 years ago
5 0
The answer is C thank youu
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Find the 30th term of the following sequence. 1, 7, 13, 19, ... 174 175 180 181.
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Checking if the sequence is an arithmetic sequence 7 - 1 = 6 13 – 7 = 6 Therefore the sequence is arithmetic, with a_0 = 1 and d = 6 a_n = a_0 + (n-1)d a_30 = 1 + (29)(6) = 175 Therefore the 30th term is 175.
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What is the measure of XYZ shown in the diagram below?
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Show the processes for solving 2x+3y=5 and 4x - y=17 using elimination and substitution
r-ruslan [8.4K]

<u>ANSWER:  </u>

The solution of the two equations 2x+3y=5 and 4x - y=17 is (4, -1).

<u>SOLUTION: </u>

Given, two linear equations are 2x + 3y = 5 → (1) and 4x – y = 17 → (2).

Let us first solve the above equations using <em>elimination process. </em>

For elimination, one of the coefficients of variables has to be same in order to cancel them.

Now solve (1) and (2)

eqn (1) \times 2 → 4x + 6y = 10

eqn (2) → 4x – y = 17

(-) ----------------------------

     0x + 7y = -7

y = -1

Substitute y value in (2)

4 x-(-1)=17 \rightarrow 4 x+1=17 \rightarrow 4 x=17-1 \rightarrow 4 x=16 \rightarrow x=4

So, solution of two equations is (4, -1).

<u><em>Now let us solve using substitution process.</em></u>

Then, (2) → 4x – y = 17 → 4x = 17 + y → y = 4x – 17

Now substitute y value in (1) → 2x + 3(4x – 17) = 5 → 2x + 12x – 51 = 5 → 14x = 5 + 51 → 14x = 56  

x = 4

Substitute x value in (2) → y = 4(4) – 17 → y = 16 – 17 → y = -1

Hence, the solution of the two equations is (4, -1).

7 0
3 years ago
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