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Tresset [83]
2 years ago
5

Find the area under the standard normal curve that lies between z = −2.30 and z = 1.08

Mathematics
1 answer:
Vilka [71]2 years ago
5 0
The answer is C thank youu
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1) You are designing a new kiddie soccer arena. The area of the rectangular
nikdorinn [45]

Answer:

The length of the rectangular field is 12 ft and the width is 5 ft.

Step-by-step explanation:

The area of a rectangle is:

\text{Area} = \text{length}\times \text{width}

The area of a rectangular field is, <em>A</em> = 60 ft.

The length of the field is:

l = w + 7

Compute the width of the field as follows:

\text{Area} = \text{length}\times \text{width}

60=(w+7)\times w\\\\60=w^{2}+7w\\\\w^{2}+7w-60=0\\

Factorize the last equation by splitting the middle term as follows:

w^{2}+7w-60=0\\w^{2}+12w-5w-60=0\\w(w+12)-5(w+12)=0\\(w-5)(w+12)=0

Now, since the width of rectangular field cannot be negative, the width is 5 ft.

Compute the length as follows:

l = w + 7

 = 5 + 7

 = 12

The length of the rectangular field is 12 ft.

7 0
2 years ago
If x² + x - 6=0, then x=
alexgriva [62]

Answer:

  • x = - 3 or x = 2

Step-by-step explanation:

Solve the quadratic equation by factorizasion

  • x² + x - 6 = 0
  • x² - 2x + 3x - 6 = 0
  • x(x - 2) + 3(x - 2) = 0
  • (x + 3)(x - 2) = 0
  • x + 3 = 0 or x - 2 = 0
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5 0
1 year ago
The distance of a point P(x, y) from the origin O(0, 0) is given by OP=__​
Naily [24]

Answer:-

\boxed{\sf \sqrt{x^2+y^2}}

Explanation:-

  • P(x,y)
  • O(0,0)

We know distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

\\ \sf\longmapsto OP=\sqrt{(0-x)^2+(0-y)^2}

\\ \sf\longmapsto OP=\sqrt{(-x)^2+(-y)^2}

\\ \sf\longmapsto OP=\sqrt{x^2+y^2}

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3 years ago
Margaret and Donovan are twins. They have each kept track of their heights every year since they were 5.
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2 years ago
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You write 4 different names on index cards.You shuffle the cards and then lay them out in a row. What is probability that they w
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It would be B- 1/24. 

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3 years ago
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