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4 years ago

Can someone please help me it would mean a lot! 3x - 4 = 6 + x

Mathematics

2 answers:

yuradex [85]4 years ago

6 0

Answer:

x=5

Step-by-step explanation:

3x-4=6+x

You want to get x by itself. So, you would subtract x from the right side, and subtract it from 3x. That gives you this:

2x-4=6

Now you would add 4 to cancel out on the left side, then add it to the 6. This gives you:

2x=10

Now divide 2 from both sides and that gives you what x equals.

x=5

alekssr [168]4 years ago

5 0

It isn’t that hard, just practice on your free time X=5

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I need help please and thank you

dem82 [27]

So we see that the ratio between the two octagons is 7:1, since 28/4=7 so what we do next is multiply the values of the smaller octagon by 7. But that’s the long way. There’s actually a shortcut by multiplying the perimeter of the smaller octagon, 34, by 7. This in turn equals 238.

6 0

4 years ago

Read 2 more answers

Jeri's lawn service charges an initial fee of $4.50 plus $3 an hour. If she is asked to

STALIN [3.7K]

Answer:

5 hours 22 minutes

Step-by-step explanation:

Let us represent the number of hours that Jeri worked as: h

Jeri's lawn service charges an initial fee of $4.50 plus $3 an hour

= $4.50 + $3 × h

= $4.50 + 3h

If she is asked to start before 7 a.m. Jeri charges 1.5 times the regular amount.

= 1.5 × ($4.50 + 3h)

If she made $29.25 on a job that began at 5 am, how many hours did Jeri work?

Hence, we have the final equation;

= 1.5 × ($4.50 + 3h) = $29.25

= 6.75 + 4.5h = 29.25

Collect like terms

= 4.5h = 29.25 - 6.75

4.5h = 22.5

h = 22.5/4.5

h = 5.3571428571

Approximately= 5.36 hours

1 hour = 60 minutes

0.36 hour =

60 × 0.36

= 21.6 minutes

Approximately ≈ 22 minutes

Therefore, Jeri worked for 5 hours 22 minutes

7 0

3 years ago

For each of the following sequences, • Give a formula for the nth term in the sequence, • Give a recursive definition for the se

Andrew [12]

Answer:

(a) $n^{th} = n$

$f(1) = 1$

$f(n) = f(n-1) + 1$

(b) $n^{th} = 2^{n-1}$

$f(1) = 1$

$f(n) = f(n-1) * 2$

$f(1) = 1$

$f(n) = f(n-1) * n$

Step-by-step explanation:

(a) This is a sequence of consecutive number

$n^{th} = n$

$f(1) = 1$

$f(n) = f(n-1) + 1$

(b) This is a sequence of 2 to the power of n - 1. The next number is twice time of this number

$n^{th} = 2^{n-1}$

$f(1) = 1$

$f(n) = f(n-1) * 2$

$n^{th} = n!$

$f(1) = 1$

$f(n) = f(n-1) * n$

5 0

3 years ago

When a fair coin is flipped, what is the chance of getting about 50% heads- specifically between 40% and 60% heads for n=10 flip

aleksklad [387]

At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide

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3 years ago

Fill in the blanks for each box

Aliun [14]

Answer:

Step-by-step explanation:

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3 years ago