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3241004551 [841]
3 years ago
7

Find the zeros of the function. Enter the solutions from least to greatest. f(x) = (x - 1)^2-36

Mathematics
1 answer:
aev [14]3 years ago
8 0

Answer:-5 and 7

Step-by-step explanation:

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Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0
3 years ago
The answer to the following q.
Katen [24]

Answer:

See below ~

Step-by-step explanation:

Given :

⇒ m∠1 = m∠2

⇒ HD = GF

=============================================================

To Prove :

<u>Δ EHD ≅ Δ EGF</u>

<u />

============================================================

Solving :

⇒ m∠1 = m∠2 (Given)

⇒ HD = GF (Given)

⇒ ∠E = ∠E (Common angle)

⇒ ΔEHD ≅ ΔEGF (AAS congruence)

3 0
1 year ago
Read 2 more answers
H E L P<br> what is the slope??
earnstyle [38]
1/3 is the slope
X= 12-6=6
Y= 4-2=2
I got the slope 1/3 I used the points (6,2), (12.4)
7 0
3 years ago
If f(x) = x2 is vertically stretched by a factor of 4 to g(x) and reflected over the x-axis, what is the equation for g(x)?​
alexdok [17]

Step-by-step explanation:

integral fx = gx, gx = fx

gx = -4x2

variable of x2 = replace to left side it mean we got minus when Variable replace to left it mean minus

8 0
2 years ago
PLEASE PLEASE HELP!!!
nignag [31]

Answer:

Step-by-step explanation:

x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} \beta \beta \alpha \neq \geq \\ \left \{ {{y=2} \atop {x=2}} \right.

3 0
3 years ago
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