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The true statement is:
"The range of the function is all real numbers less than or equal to 9."
<h3>Which statements are true?</h3>
Here we have the quadratic function:
And we want to see which of the given statements are true.
The first one is:
"The domain is al real numbers less than or equal to -2"
This is false, for all quadratic functions the domain is the set of all real numbers (unless the domain is defined).
The second statement is:
" The domain of the function is all real numbers less than or equal to 9."
Also false
Third one:
" The range of the function is all real numbers less than or equal to −2"
The range of a quadratic function with a negative leading coefficient will be the set of all the values smaller than the y-value of the vertex.
In this case, the quadratic function is:
So the vertex is at:
Then the y-value of the vertex is:
So the range is the set of all real numbers less than or equal to 9.
So the above statement is false, and the final one:
"The range of the function is all real numbers less than or equal to 9."
Is the true statement.
If you want to learn more about quadratic functions:
#SPJ1
Answer:
1 and 2.
Midpoints calculated, plotted and connected to make the triangle DEF, see the attached.
- D= (-2, 2), E = (-1, -2), F = (-4, -1)
3.
As per definition, midsegment is parallel to a side.
Parallel lines have same slope.
<u>Find slopes of FD and CB and compare. </u>
- m(FD) = (2 - (-1))/(-2 -(-4)) = 3/2
- m(CB) = (1 - (-5))/(1 - (-3)) = 6/4 = 3/2
- As we see the slopes are same
<u>Find the slopes of FE and AB and compare.</u>
- m(FE) = (-2 - (- 1))/(-1 - (-4)) = -1/3
- m(AB) = (1 - 3)/(1 - (-5)) = -2/6 = -1/3
- Slopes are same
<u>Find the slopes of DE and AC and compare.</u>
- m(DE) = (-2 - 2)/(-1 - (-2)) = -4/1 = -4
- m(AC) = (-5 - 3)/(-3 - (-5)) = -8/2 = -4
- Slopes are same
4.
As per definition, midsegment is half the parallel side.
<u>We'll show that FD = 1/2CB</u>
- FD =
=
=
- CB =
=
= 2
- As we see FD = 1/2CB
<u>FE = 1/2AB</u>
- FE =
=
=
- AB =
=
= 2
- As we see FE = 1/2AB
<u>DE = 1/2AC</u>
- DE =
=
=
- AC =
=
= 2
- As we see DE = 1/2AC
