parallelograms and relatively even shapes, so how ever far apart the bottom two vertices are apart is how far apart you would space the top ones. simply add the x coordinates absolute values (meaning ignore negative values for now) 6+0=0. 6 Units away from 3( top vertex is (3,7)) would be -3. for the y coordinates you gotta look at y coordinates of the top vertex and bottom right vertex. they're ten units apart. go ten up from -5( because the bottom left vertex is (-6,-5) and you get 5. so overall (-3,5) would be the last vertex
Since parallelograms are relatively even shapes, the distance between the bottom two vertices determines the distance between the top two. Simply add the absolute values of the x coordinates (meaning ignore negative values for now) 6 + 0 = 0 -3 is 6 units away from 3 (top vertex is (3,7)). Look at the y coordinates of the top vertex and bottom right vertex for the y coordinates. They're separated by ten units. Since the bottom left vertex is (-6,-5) and you get 5, go ten up from -5.
