Answer: When t = 4.25 R(t) = D(t)
This tells you that at 4.25 seconds into their flights, both the Rocket and the Drone were at a height of 20 feet.
Step-by-step explanation: The point where the two graphed lines cross is where the values are equal.
The Drone has been hovering at 20 feet between 2 and 5 seconds. The Rocket passed through that height for a brief (millisecond) time as it was falling back to the ground.
Without grid lines it is my best estimation (using a ruler to create a verticla line from the intersection of the lines to the time scale) that t = 4.25. It is between 4 and 4.5 seconds.
The surface area of a cylinder is define by the formula S.A.=2πrh+2<span>πr^2, where the first part of the formula refers to the lateral area, perimeter, or circumference and the second part to the area of the bases, which are circles.
On this exercise it is asked to find the lateral area of a cylinder whose radius is 6 cm, and has a height of 20cm. To find the lateral area of the cylinder you should substitute this values into the formula, S.A.=2</span>πrh, and as can be seen the answers are given in terms of <span>π or pi.
S.A.=2</span><span>πrh
S.A.=2</span><span>π(6cm)(20cm)
S.A.=2</span><span>π(120cm)
S.A.=240</span>π cm^2
The lateral area of the cylinder is 240<span>π cm^2 or in other words letter B from the given choices.</span>
Answer:x=-7
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
2+2+2+2=8
2*4=8
