D.) A polynomial cannot have a variable in the denominator.
Given:
w be the weight in pounds of a baby tigers.
To find:
The inequality if baby tigers can be no larger than 4 pounds.
Solution:
Baby tigers can be no larger than 4 pounds. It mean weight of baby tigers cannot be greater than 4. In other words, the weight of the baby tigers must be less than or equal to 4.
Let w represents weight in pounds and the weight of the baby tigers must be less than or equal to 4. So,
Therefore, the required inequality is .
Answer:
Step-by-step explanation:
Given the Total revenue R(x) = 2x
Cost C(x) = 0.01x²+0.3x+30 where;
x = 30 and dx/dt = 9units per day.
Rate of change of revenue dR/dt = dR/dx • dx/dt
dR/dt = 2dx/dt
dR/dt = 2(9) = $18
Rate of change of revenue with respect to time is 18dollars/day.
Rate of change of cost dC/dt = dC/dx • dx/dt
dC/dt = (0.02x+0.3)dx/dt
dC/dt at x = 30 and dx/dt = 9 will give;
dC/dt = {0.02(30)+0.3}×9
dC/dt = (0.6+0.3) × 9
dC/dt = 0.9×9
dC/dt = $8.1
Rate of change of cost with respect to time is 8.1dollars/day
Profit = Revenue - Cost
Profit = 18-8.1
Daily Profit = $9.9
3(5y-6)-2y=8
15y-18-2y=8
13y-18=8
13y=26
y=2
That is because you have the expression you can substitute it on the system.( hope this helps)
Answer:
Step-by-step explanation:
Given that points scored is the dependent variable Y and Number of people attending the game is the independent variable is independent variable x
The correlation coefficient, slope and intercept are calculated as shown below:
x y
378 54
350 57
320 59
478 80
451 82
250 75
489 73
451 53
410 67
215 78
113 67
250 56
450 85
489 101
472 99
Mean 371.0666667 72.4
std dev 117.5138087 15.42632259
covariance 667.5733333
r 0.394558035
Slope 3.005642934
Intercept 153.4581182
y = 3.006x+153.46 is the regression line.
Corre = 0.3945 (weak positive)
