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3 years ago

The first term in this sequence is -1. Which function represents a recursive definition of the sequence?

Mathematics

1 answer:

Llana [10]3 years ago

4 0

Answer:

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Please answer. I will give you brainliest

aleksandrvk [35]

Answer:

The third one

Step-by-step explanation:

If you look at the graph you see that the relationship between the points is linear positive correlation

Therefore c is your answer :)

7 0

3 years ago

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slega [8]

ARST was translated, then dilated, to create AZXY

3 0

2 years ago

I need help .. so can somebody help me please ? what two number and get 10 and -24 ?

Trava [24]

What 2 numbers do you multiply to get 10? In other words, what number can you multiply with another number to get 10?

The formula to solve this would be:

X x Y = 10

There are at least two combinations of two numbers that you can multiply together to get 10.

For your convenience, we have made a list of all the combinations of two numbers multiplied by each other that will make 10:

<span>1 x 10 = 10
2 x 5 = 10
5 x 2 = 10
10 x 1 = 10
</span>

6 0

3 years ago

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12 out of 15 people in the US like to eat out. if 400 people selected eating out how many people took the survey?

butalik [34]

12/15 = 400/500

500 people took the survey.

3 0

3 years ago

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

3 years ago

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