Question

Re-write the equation without the h component.

Answer 1

Answer:

$f(x) = 2[\frac{3^x}{9}] + 2$

$f(x) = 8(4)^x$

Step-by-step explanation:

Given

$f(x) = 2(3)^{x-2} + 2$

$f(x) = \frac{1}{2}(4)^{x+2}$

Required

Remove the h component

In a function, the h component is highlighted as:

$f(x) = a^{x+h}$

So, we have:

$f(x) = 2(3)^{x-2} + 2$

Split the exponents using the following law of indices:

$a^m/a^n = a^{m-n}$

$f(x) = 2*\frac{3^x}{3^2} + 2$

$f(x) = 2*\frac{3^x}{9} + 2$

$f(x) = 2[\frac{3^x}{9}] + 2$

The h component has been removed

$f(x) = \frac{1}{2}(4)^{x+2}$

Split the exponent using the following law of indices

$a^{m+n} =a^m * a^n$

So, we have:

$f(x) = \frac{1}{2}(4)^x * 4^2$

Express 4^2 as 16

$f(x) = \frac{1}{2}(4)^x * 16$

Divide 16 by 2

$f(x) = 8(4)^x$