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Leokris [45]
3 years ago
13

How many answers does this equation have? 77-x=(77+x)*-1

Mathematics
2 answers:
kvv77 [185]3 years ago
7 0

it should only be 1 I think

Airida [17]3 years ago
3 0

Answer: Infinite solutions

Step-by-step explanation: When you simplify both sides you get

-77-x=-77-x

-x=-x so there are infinite possibilities for x.

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Can someone solve this
marishachu [46]

Answer:

x = -44.3

Step-by-step explanation:

2x+450 = 7-8x

Add 8x to each side

2x+8x+450 = 7-8x+8x

10x+450 =7

Subtract 450 from each side

10x+450-450 = 7-450

10x = -443

Divide each side by 10

10x/10 = -443/10

x = -44.3

7 0
3 years ago
Where does the helix r(t) = cos(πt), sin(πt), t intersect the paraboloid z = x2 + y2? (x, y, z) = What is the angle of intersect
Colt1911 [192]

Answer:

Intersection at (-1, 0, 1).

Angle 0.6 radians

Step-by-step explanation:

The helix r(t) = (cos(πt), sin(πt), t) intersects the paraboloid  

z = x2 + y2 when the coordinates (x,y,z)=(cos(πt), sin(πt), t) of the helix satisfy the equation of the paraboloid. That is, when

\bf (cos(\pi t), sin(\pi t), t)

But  

\bf cos^2(\pi t)+sin^2(\pi t)=1

so, the helix intersects the paraboloid when t=1. This is the point

(cos(π), sin(π), 1) = (-1, 0, 1)

The angle of intersection between the helix and the paraboloid is the angle between the tangent vector to the curve and the tangent plane to the paraboloid.

The <em>tangent vector</em> to the helix in t=1 is

r'(t) when t=1

r'(t) = (-πsin(πt), πcos(πt), 1), hence

r'(1) = (0, -π, 1)

A normal vector to the tangent plane of the surface  

\bf z=x^2+y^2

at the point (-1, 0, 1) is given by

\bf (\frac{\partial f}{\partial x}(-1,0),\frac{\partial f}{\partial y}(-1,0),-1)

where

\bf f(x,y)=x^2+y^2

since

\bf \frac{\partial f}{\partial x}=2x,\;\frac{\partial f}{\partial y}=2y

so, a normal vector to the tangent plane is

(-2,0,-1)

Hence, <em>a vector in the same direction as the projection of the helix's tangent vector (0, -π, 1) onto the tangent plane </em>is given by

\bf (0,-\pi,1)-((0,-\pi,1)\bullet(-2,0,-1))(-2,0,1)=(0,-\pi,1)-(-2,0,1)=(2,-\pi,0)

The angle between the tangent vector to the curve and the tangent plane to the paraboloid equals the angle between the tangent vector to the curve and the vector we just found.  

But we now

\bf (2,-\pi,0)\bullet(0,-\pi,1)=\parallel(2,-\pi,0)\parallel\parallel(0,-\pi,1)\parallel cos\theta

where  

\bf \theta= angle between the tangent vector and its projection onto the tangent plane. So

\bf \pi^2=(\sqrt{4+\pi^2}\sqrt{\pi^2+1})cos\theta\rightarrow cos\theta=\frac{\pi^2}{\sqrt{4+\pi^2}\sqrt{\pi^2+1}}=0.8038

and

\bf \theta=arccos(0.8038)=0.6371\;radians

7 0
3 years ago
Which of the following is equal to 7 1/4?
marysya [2.9K]

Answer:

C

Step-by-step explanation:

7^{\tfrac 14} = \sqrt[4]{7}

4 0
3 years ago
How do u make x the subject in m=n+x/p
katrin [286]
(p)m=n+x/p(p)
mp-n=n+x-n
mp-n=x
3 0
3 years ago
Read 2 more answers
What is the area of this trapezoid, I WILL GIVE BRAINLIEST TO THE CORRECT ANSWER! URGENT WORTH 90PTS
tresset_1 [31]
192 in.

Hope this helped! ♡
6 0
3 years ago
Read 2 more answers
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