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2 years ago

PLEASE HELP ME DUE SOON ILL MARK AS BRAINLIEST!! Find M∠1 and M∠3 in the kite.

Mathematics

1 answer:

QveST [7]2 years ago

7 0

Answer:

1 = 39 degrees (some theorem, like triangles sharing a bisector or something sorry)

3 = 51 degrees (if 1=39 and 2=90 degrees since its on a right angle, and a triangle's angles add up to 180, then you subtract 1 and 2 from 180 and get 51

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Step-by-step explanation:

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Given:

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To find:

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Solution:

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$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(3-(-3))^2+(4-4)^2}$

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Similarly,

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And,

$AC=\sqrt{(3-(-3))^2+(-4-4)^2}$

$AC=\sqrt{(6)^2+(-8)^2}$

$AC=\sqrt{36+64}$

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Now, taking sum of squares of two smaller sides, we get

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$AB^2+BC^2=100$

$AB^2+BC^2=AC^2$

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2 years ago

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