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Sveta_85 [38]
2 years ago
12

If a tennis ball has a diameter of 14, What is the volume of the tennis ball in terms of pie?

Mathematics
2 answers:
katrin [286]2 years ago
8 0

Answer:

the volume of the tennis ball is 1436

Step-by-step explanation:

notsponge [240]2 years ago
8 0

Answer:

1437.33

Step-by-step explanation:

first,

r = d/2

r = 14/2

r = 7

now,

4/3πr³

4/3 × 22/7 (7)³ [ π = 22/7]

88/21 × 343

30184/21

1437.33

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What is the value of the missing exponent in the equation 7.4 ÷ 10= 0.074?
KiRa [710]

the answer is 0.74 not 0.074

Step-by-step explanation:

<h3>7.4 <u><em>÷ </em></u><em> 10 = 0.74</em></h3>
7 0
2 years ago
What is the absolute value of –6? Use the number line to help answer the question. A number line going from negative 7 to positi
drek231 [11]
<h3>Answer:  6</h3>

Mark the locations -6 and 0 on the number line. Note that going from -6 to 0, or vice versa, will take exactly 6 steps. Put another way, the distance between 0 and -6 is 6 units. Absolute value represents distance, so it is never negative.

We say |-6| = 6

Effectively, all we're doing is removing the negative sign.

6 0
2 years ago
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Hi can someone help me with this
Ad libitum [116K]

Answer:

25 units

Step-by-step explanation:

Applying Pythagoras' Theorem,

(BD)^2= (CD)^2 + (BC)^2

(BC)^2= 65^2 - 60^2

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5 0
3 years ago
How do you find the zeros of an equation​
lubasha [3.4K]

Answer:

Step-by-step explanation:

In general, given the function, f(x), its zeros can be found by setting the function to zero. The values of x that represent the set equation are the zeroes of the function. To find the zeros of a function, find the values of x where f(x) = 0.

5 0
2 years ago
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Help mi out plz..... solve using matrix method​
HACTEHA [7]

Answer:

x = \frac{22}{7}

y = \frac{3}7}

Step-by-step explanation:

2x-3y=5\\5x=4y=14\\\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right] \left[\begin{array}{c}x\\y\\\end{array}\right] =\left[\begin{array}{c}5\\14\\\end{array}\right]

Let A = \\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right]

The inverse of A multiplied by A = the identity matrix \left[\begin{array}{cc}1&0\\0&1\\\end{array}\right]

Inverse of A = \frac{1}{detA} \left[\begin{array}{ccc}-4&3\\-5&2\\\end{array}\right]

detA = ad - bc = -8 - - 15 = 7

Inverse of A = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right] \left[\begin{array}{ccc}5\\14\\\end{array}\right] = \left[\begin{array}{ccc}\frac{22}{7} \\\frac{3}{7} \\\end{array}\right]

5 0
3 years ago
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